What determines the direction of a reaction under standard state conditions?

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SUMMARY

The discussion centers on the determination of reaction direction under standard state conditions, specifically using Gibbs free energy (ΔG) and standard Gibbs free energy (ΔG°). The correct answer for the reaction's Gibbs free energy change is 28.76 kJ/mol. It is established that if ΔG > 0, the reaction proceeds to the left, indicating that the reverse reaction is spontaneous under standard state conditions. The standard state is defined as having reactants and products at 1M concentration, which influences the reaction quotient (Q) and equilibrium constant (K).

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Homework Statement
If reactants and products were mixed in their standard-state concentrations,which direction would the reaction proceed?
Relevant Equations
Δ G = Δ H − T Δ S
Δ G = -RT ln K
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For (1), I got the correct answer which is 28.76kj/mol.
For (2), the answer given is since Δ G > 0, the reaction proceed to left. I understand the meaning but what means by ' If reactants and products were mixed in their standard-state concentrations', is it indicate it is under standard state therefore just using the Δ G (standard) to determine the direction? As my first thought relates to the increasing in volume or concentration.
 
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You can do it two ways; standard state here means concentration = 1M, so if you plug this value into al the concentrations in the expression for Q, the reaction quotient, you will find that Q >> K, so reaction has to proceed to the left to reduce product concentrations and increase reagent concentrations until Q = K. Alternatively, if you have already calculated ΔG°, which you have, observing that ΔG° is positive means that the reverse reaction is spontaneous when everything is in the standard state.
(Note: be careful to distinguish between ΔG and ΔG°; you need to do this for part 3.)
 
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