What Determines the Frequency of a de Broglie Wave?

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SUMMARY

The frequency of a de Broglie wave can be calculated using the formula f = v / λ, where v is the speed of the particle and λ is the wavelength. For an electron with a wavelength of 1.2 x 10-10 m, the calculated frequency is 5.05 x 1016 Hz. The discussion highlights the distinction between phase velocity and group velocity in relation to frequency calculations, emphasizing that phase velocity is typically greater than the speed of light (c) and may lead to confusion in interpretation. Additionally, the relationship between de Broglie wave energy and kinetic energy is clarified, noting that the energy expression used in calculations does not equate to the actual energy of the particle.

PREREQUISITES
  • Understanding of de Broglie wavelength (λ = h/mv)
  • Familiarity with wave mechanics (v = fλ)
  • Knowledge of relativistic mass and energy equations (E = mc²)
  • Concept of phase and group velocities in wave theory
NEXT STEPS
  • Explore the implications of relativistic effects on de Broglie waves
  • Learn about the differences between phase velocity and group velocity in quantum mechanics
  • Investigate the relationship between wave energy and kinetic energy in quantum particles
  • Study the application of the de Broglie hypothesis in modern physics
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Physics students, quantum mechanics researchers, and anyone interested in the wave-particle duality of matter will benefit from this discussion.

yogifromindia
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I am confused about de Broglie waves.

we know λ = h/mv

What is the frequency of the dB wave?

Generally, speed of any wave v = fλ.

Is the frequency of dB wave f = v / λ, where v is the speed of the particle (ignoring Special relativity effects)?
 
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Here is a tricky question: How do you define or measure the frequency of a de-Broglie wave?

With v = fλ, you get f=v / λ = mv2/h.
 
So if the wavelength of an electron is 1.2 x 10e(-10), what is its frequency?

Knowing λ, I can calculate the electron's velocity as v = h/mλ. I get v = 6.07 x 10e(6).

And now f = v/λ, which comes to 5.05 x 10e(16).

Is this right?
 
yogifromindia said:
So if the wavelength of an electron is 1.2 x 10e(-10), what is its frequency?

Knowing λ, I can calculate the electron's velocity as v = h/mλ. I get v = 6.07 x 10e(6).

And now f = v/λ, which comes to 5.05 x 10e(16).

Is this right?

Yeep!
 
mfb said:
Here is a tricky question: How do you define or measure the frequency of a de-Broglie wave?

With v = fλ, you get f=v / λ = mv2/h.

Using this relation, energy of wave = hf = mv2.

What does mv2 mean? We know mv2/2 is K.E. of the particle. Why is the energy of dB wave twice the K.E.?
 
yogifromindia said:
Why is the energy of dB wave twice the K.E.?
It is not the energy, it is just an expression which is used in calculations.

In relativistic quantum mechanics, this is easier (!): you get the total energy of the particle.
 
mfb said:
It is not the energy, it is just an expression which is used in calculations.

In relativistic quantum mechanics, this is easier (!): you get the total energy of the particle.

Do you mean to say if i plugged in the relativistic formula for Mass, hf will be equal to the rest energy (m0c2) plus kinetic energy of particle mv2/2 (where m0 is rest mass and m is the relativistic mass)?

I also understand dB waves have phase and group velocities (and phase velocity is generally greater than c). While calculating frequency of dB wave using f = v/λ, is v the phase velocity or the group velocity? I would think phase velocity would be right as that is the actual wave velocity (but I am also confused because we generally disregard phase velocity as it is greater than c).
 
There is the problem.
v in the momentum is group velocity, but if you use the group velocity in your frequency equation it is unclear (at least to me) what that "frequency" means. Phase velocity gives the usual meaning of frequency.

yogifromindia said:
Do you mean to say if i plugged in the relativistic formula for Mass, hf will be equal to the rest energy (m0c2) plus kinetic energy of particle mv2/2 (where m0 is rest mass and m is the relativistic mass)?
mv^2/2 is not the relativistic kinetic energy. The total energy is ##\gamma m c^2## and you'll see this expression in the time-dependence of the particle.
 
Ok i did some math, but am no close to solution. I am able to reconcile Special Relativity energies, and I am also able to relate it to the dB wave's energy. But not sure if i still understand it. Here is what I did.

Take an electron traveling at 2.5 x 108 m/s (relativistic effects will be significant).

First the Special Releativity:

Rest Mass m0 = 9.1 x 10-31 kg

Relativistic Mass mr = m0/√1-(v2/c2) = 1.64x10-30 kg

Momentum P = mr x v = 1.64 x 10-30 x 2.5 x 108 = 4.12 x 10-22 kg-m/s

Rest Energy = m0c2 = 8.19 x 10-14 J
Total Energy = mrc2 = 1.48 x 10-13 J

As per S/R:

(mrc2)2 = (m0c2)2 + (cp)2

This relation reconciles.

Now the dB part:

dB Wavelength λ = h/p = 6.63 x 10-34 / 4.12 x 10-22 = 1.6 x 10-12 m

Since in this discussion we are not sure whether vphase or v should be used in frequency calculation, I have tried doing with both.

Phase Velocity vphase = c2/v = 3.6 x 108 m/s

Frequency calculated using Phase Velocity
fphase = vphase / λ = 2.25 x 1020 Hz

Frequency calculated using Group Velocity
fgroup = v / λ = 1.56 x 1020 Hz

(Note v is same as vgroup)

Energy calculated using Frequency based on Phase Velocity
Ephase = hfphase = 6.63 x 10-34 x 2.25 x 1020 J = 1.49 x 10-13 J

Energy calculated using Frequency based on Group Velocity
Egroup = hfgroup = 6.63 x 10-34 x 1.56 x 1020 J = 1.03 x 10-13 J

Now if you see here Ephase is same as TotalEnergy

i.e. hvphase/λ = mrc2

But I am still confused...what sense can be made of this? What exactly is Vphase?
 

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