What Determines the Rank and Dimension of a Matrix's Solution Space?

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The discussion centers on determining the rank and dimension of a matrix's solution space, specifically for the matrix provided. The row rank is calculated as 2, derived from its reduced echelon form. According to the rank theorem, the column rank is also confirmed to be 2. Consequently, the dimension of the solution space for the equation Mx=0 is determined to be 2, calculated as the number of columns minus the rank.

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  • Familiarity with the rank theorem in linear algebra
  • Knowledge of linear independence in matrix rows
  • Basic concepts of solution spaces in linear equations
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(a)Determine the row rank of the matrix,

1 1 1 1
1 1 2 5
2 2 0 -6

(b) What is the column rank of this matrix?
(c) What is the dimension of the solution space Mx=0

So this is my answer:

I have reduced my matrix into echelon form and i get

1 1 1 1
0 0 -1 -4
0 0 0 0

Therefore my row rank is 2 (the number of linearly independent rows)

Since by rank theorem, (row rank = column rank = determinental rank) the column rank is also 2.

And the dimension of the solution space is 2 (number of columns - rank)

Is this answer correct?

Thank you
Dylan
 
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yes, i think so
 

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