What did I do wrong in this Bessel equation?

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SUMMARY

The discussion revolves around converting the differential equation \(x^{2}y''+2xy'+[kx^{2}-n(n+1)]y=0\) into a standard Modified Bessel Equation using the substitution \(y=x^{-\frac{1}{2}}w\). The user, Alan, initially struggles with the transformation due to an arithmetic error in the exponent and misinterpretation of the final equation. After clarification from other forum members, it is established that the correct transformation leads to a constant term of \(-(n+\frac{1}{2})^{2}\), resolving Alan's confusion.

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yungman
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I need to convertx^{2}y''+2xy'+[kx^{2}-n(n+1)]y=0 using y=x^{-\frac{1}{2}}w to a normal Modified Bessel Equation and I cannot get to that. I check many times and I must be having a blind spot!

This is my work:

y=x^{-\frac{1}{2}} w \Rightarrow y'=-\frac{1}{2}x^{-\frac{3}{2}}w+x^{-\frac{1}{2}}w' \Rightarrow y''=\frac{3}{4}x^{-\frac{5}{2}}w-\frac{1}{2}x^{-\frac{3}{2}}w'+x^{-\frac{1}{2}}w''-\frac{1}{2}x^{-\frac{3}{2}}w'

x^{2}y''+2xy'+(kx^{2}-n(n+1))y=0 \Rightarrow

[\frac{3}{4}x^{-\frac{1}{2}}w-\frac{1}{2}x^{\frac{1}{2}}w'+x^{\frac{3}{2}}w''-\frac{1}{2}x^{\frac{1}{2}}w']+[2x^{\frac{1}{2}}w'-x^{-\frac{1}{2}}w]+[kx^{\frac{3}{2}}w-n(n+1)x^{-\frac{1}{2}})w]=0


Grouping w'', w' and w terms:

x^{\frac{3}{2}}w''+(-x^{\frac{1}{2}}+2x^{\frac{1}{2}})w'+(\frac{3}{4}x^{-\frac{1}{2}}-x^{-\frac{1}{2}}+kx^{\frac{3}{2}}-n(n+1)x^{-\frac{1}{2}})w=0

Multiply by x^{\frac{1}{2}} This give:

x^{2}w''+xw'+(\frac{3}{4}-1+kx^{2}-n(n+1))w=0

I can't get the standard Modified Bessel equation because the 3/4-1 in the w term cannot be cancel out.
Please tell me what I did wrong.

Thanks
Alan
 
Last edited:
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Your arithmetic is correct (except that in the first line you have an exponent -\frac23 that should be -\frac32, but later steps are correct).

Is there any reason why the n (order) in the equation you end up with is required to be the same you began with? I notice that your problematic constant term is -n^2 - n - \frac14, which factors nicely.
 
ystael said:
Your arithmetic is correct (except that in the first line you have an exponent -\frac23 that should be -\frac32, but later steps are correct).

Is there any reason why the n (order) in the equation you end up with is required to be the same you began with? I notice that your problematic constant term is -n^2 - n - \frac14, which factors nicely.

You are right, I was blind! The final equation is with (n+\frac{1}{2})^{2}!

It must be old age! I read the final equation wrong and I just kept concentrate on what I did and never look at the final equation! Wasted almost an hour on this! The only excuse I can come up is I am 56! Too old!:rolleyes: BUT I am not old enough to conceed to you guys yet!

Thanks a million.

Alan
 
Last edited:

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