What Distance is Required to Stop a Car Moving at 50 m/s?

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SUMMARY

The discussion focuses on calculating the stopping distance of a car moving at 50 m/s, given that a car moving at 25 m/s requires 50 m to stop. The correct stopping distance for the faster car is determined to be 200 m using the formula Vf^2 = Vi^2 + 2ad. The deceleration is calculated as -6.25 m/s², leading to the conclusion that a direct ratio between distance and velocity is incorrect in this context. The final answer is confirmed as option C, 200 m.

PREREQUISITES
  • Understanding of kinematic equations, specifically Vf^2 = Vi^2 + 2ad
  • Knowledge of basic physics concepts such as velocity, acceleration, and deceleration
  • Ability to manipulate algebraic equations to solve for unknowns
  • Familiarity with units of measurement in physics (meters, seconds)
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  • Study the derivation and application of kinematic equations in physics
  • Learn about the effects of different deceleration rates on stopping distances
  • Explore real-world applications of stopping distance calculations in automotive safety
  • Investigate the relationship between speed, stopping distance, and reaction time in driving scenarios
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This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and safety measures related to stopping distances.

Soaring Crane
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If it takes 50 m to stop a car initially moving at 25 m/s, what distance is required to stop a car moving at 50 m/s under the same condition?

a. 50 m
b. 100 m
c. 200 m
d. 400 m

This is probably a really easy question, but I just can't see how to work it out. I tried to set up a ratio between the distance and velocity and that got me 100 m, but b is incorrect. Can anyone explain the correct method to do this problem and tell me why setting up a ratio between those 2 components is a mistake?
 
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Answer is C

Vf^2=Vi^2+2ad
0=25^2+2(a)50
a=-6.25m/s^2

now you know the deceleration of the car

Vf^2=Vi^2+2ad
0=50^2+2(6.25)d
d=200m
 
Thanks. Is this the only way you can solve it?
 
This is the way I would solve it. Hope others give some posts
 

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