what do you do if you have to evaluate arcsin2?
Feb 20, 2007 #2 radou Homework Helper 3,120 7 fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? Nothing, since 2 is not in the domain.
fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? Nothing, since 2 is not in the domain.
Feb 20, 2007 #3 HallsofIvy Science Advisor Homework Helper 41,847 969 [itex]-1\le sin(x) \le 1[/itex] There is no x such that sin(x)= 2 and so arcsin 2 is not defined.
Feb 21, 2007 #4 Gib Z Homework Helper 3,346 6 Perhaps get the series for it and sub in 2, see what happens :S
Feb 21, 2007 #5 dextercioby Science Advisor Homework Helper Insights Author 13,206 789 fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? It comes down to solving the equation [tex] \sin x =2 [/tex] which has no solution in [itex] \mathbb{R} [/itex], and in [itex] \mathbb{C} [/itex] has the solution [tex] x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z} [/tex]
fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? It comes down to solving the equation [tex] \sin x =2 [/tex] which has no solution in [itex] \mathbb{R} [/itex], and in [itex] \mathbb{C} [/itex] has the solution [tex] x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z} [/tex]
Feb 21, 2007 #6 arildno Science Advisor Homework Helper Gold Member Dearly Missed 10,025 135 Gib Z said: Perhaps get the series for it and sub in 2, see what happens :S Which would diverge. A Pade approximant might give you some silly number, though.
Gib Z said: Perhaps get the series for it and sub in 2, see what happens :S Which would diverge. A Pade approximant might give you some silly number, though.