What do you do if you have to evaluate arcsin2?

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Homework Help Overview

The discussion revolves around the evaluation of arcsin(2), which is outside the typical domain of the arcsine function. Participants explore the implications of this domain restriction and consider alternative approaches.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants note that arcsin(2) is not defined due to the range of the sine function. Others suggest exploring series expansions or complex solutions, raising questions about the implications of these approaches.

Discussion Status

The discussion includes various interpretations of the problem, with some participants providing insights into the nature of the arcsin function and its limitations. There is no explicit consensus, but multiple lines of reasoning are being explored.

Contextual Notes

Participants reference the domain of the sine function and the implications of evaluating arcsin(2) within real and complex numbers. The discussion reflects on the constraints of the problem and the assumptions involved.

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what do you do if you have to evaluate arcsin2?
 
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fizzzzzzzzzzzy said:
what do you do if you have to evaluate arcsin2?

Nothing, since 2 is not in the domain.
 
[itex]-1\le sin(x) \le 1[/itex]

There is no x such that sin(x)= 2 and so arcsin 2 is not defined.
 
Perhaps get the series for it and sub in 2, see what happens :S
 
fizzzzzzzzzzzy said:
what do you do if you have to evaluate arcsin2?

It comes down to solving the equation

[tex]\sin x =2[/tex]

which has no solution in [itex]\mathbb{R}[/itex], and in [itex]\mathbb{C}[/itex] has the solution

[tex]x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z}[/tex]
 
Gib Z said:
Perhaps get the series for it and sub in 2, see what happens :S

Which would diverge.
A Pade approximant might give you some silly number, though. :smile:
 

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