fizzzzzzzzzzzy
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what do you do if you have to evaluate arcsin2?
What do you do if you have to evaluate arcsin2?
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fizzzzzzzzzzzy said:
Nothing, since 2 is not in the domain.
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[itex]-1\le sin(x) \le 1[/itex]
There is no x such that sin(x)= 2 and so arcsin 2 is not defined.
There is no x such that sin(x)= 2 and so arcsin 2 is not defined.
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Perhaps get the series for it and sub in 2, see what happens :S
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fizzzzzzzzzzzy said:
It comes down to solving the equation
[tex]\sin x =2[/tex]
which has no solution in [itex]\mathbb{R}[/itex], and in [itex]\mathbb{C}[/itex] has the solution
[tex]x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z}[/tex]
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Gib Z said:
Which would diverge.
A Pade approximant might give you some silly number, though.
