fizzzzzzzzzzzy Messages 44 Reaction score 1 Thread starter Feb 20, 2007 #1 what do you do if you have to evaluate arcsin2?
radou Homework Helper Messages 3,149 Reaction score 8 Feb 20, 2007 #2 fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? Nothing, since 2 is not in the domain.
fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? Nothing, since 2 is not in the domain.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Feb 20, 2007 #3 [itex]-1\le sin(x) \le 1[/itex] There is no x such that sin(x)= 2 and so arcsin 2 is not defined.
Gib Z Homework Helper Messages 3,341 Reaction score 7 Feb 21, 2007 #4 Perhaps get the series for it and sub in 2, see what happens :S
dextercioby Science Advisor Insights Author Messages 13,419 Reaction score 4,230 Feb 21, 2007 #5 fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? It comes down to solving the equation [tex]\sin x =2[/tex] which has no solution in [itex]\mathbb{R}[/itex], and in [itex]\mathbb{C}[/itex] has the solution [tex]x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z}[/tex]
fizzzzzzzzzzzy said: what do you do if you have to evaluate arcsin2? It comes down to solving the equation [tex]\sin x =2[/tex] which has no solution in [itex]\mathbb{R}[/itex], and in [itex]\mathbb{C}[/itex] has the solution [tex]x=-i\ln\left(2\pm i\sqrt{3}\right)+2k\pi \ , \forall k\in\mathbb{Z}[/tex]
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Feb 21, 2007 #6 Gib Z said: Perhaps get the series for it and sub in 2, see what happens :S Which would diverge. A Pade approximant might give you some silly number, though.
Gib Z said: Perhaps get the series for it and sub in 2, see what happens :S Which would diverge. A Pade approximant might give you some silly number, though.