What Does a Spring Scale Read at Peak When Jumped On?

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Homework Help Overview

The discussion revolves around a physics problem involving a spring scale and the forces at play when a person jumps onto it from a height. The subject area includes concepts of mechanics, specifically relating to springs and energy conservation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to determine the reading of the scale at its peak after jumping, initially suggesting the use of the spring potential energy formula. Participants discuss how to calculate the spring constant and the relationship between kinetic and potential energy.

Discussion Status

Participants are actively engaging with the problem, with some providing calculations and others confirming the approach. There is a collaborative atmosphere as they explore the necessary equations and concepts without reaching a definitive conclusion.

Contextual Notes

There is a focus on deriving the spring constant from the given weight and compression, and participants are considering the implications of energy conservation in the context of the problem. The original poster's assumptions about the scale's behavior are also under examination.

fender5791
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If you stand on a bathroom scale, the spring inside the scale compresses 0.50 mm, and it tells you your weight is 740 N. Now if you jump on the scale from a height of 1.2 m, what does the scale read at its peak?


I'm guessing you use 1/2kx^2 but otherwise, I'm not sure.
 
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Hi fender5791! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
fender5791 said:
If you stand on a bathroom scale, the spring inside the scale compresses 0.50 mm, and it tells you your weight is 740 N.

ok, so what is the value of k? :smile:

(and yes, you can use 1/2 kx2 later)
 
So would k be (740N)/(.0005m) = 1.48x10^6 N/m?
 
Yup! :biggrin:

Now use KE + PE = constant.​
 
Got it, thanks.
 

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