Calculating Spring Compression from 1m Jump on Scale

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Homework Help Overview

The discussion revolves around calculating the spring compression of a bathroom scale when a person jumps onto it from a height of 1 meter. The subject area includes concepts from mechanics, specifically Hooke's law and conservation of mechanical energy.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using Hooke's law to find the spring constant and applying conservation of mechanical energy to relate potential energy and spring compression. There is uncertainty about the correct approach to find the reading on the scale at the peak of the jump.

Discussion Status

Some participants have provided guidance on the approach, suggesting that the gravitational potential energy can be directly equated to the potential energy stored in the spring. There is acknowledgment of possible arithmetic errors and confusion regarding unit conversions.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share. There is also a mention of significant figures affecting the results.

ace123
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If you stand on a bathroom scale, spring inside compresses .6mm, and tells your weight is 710 N. Now if you jump on the scale from a height of 1m, what does the read at it's peak?

This is what I tried to do:

I used Hooke's law: F[tex]_{}s[/tex]= k*x
and solved for the k which is spring constant.

Then I wasn't too sure of how to find the spring compression when he jumps from a height of 1m. I tried to use conservation of mechanical energy:

I did the potential energy of the the guy at 1m and set it equal to the kinetic energy when he hits the scale.

I then set up another conservation of mechanical energy for the scale. Which was Kinetic energy equal to the compression 1/2kx^2.

This is wrong however and I have no clue what else to try.

Thanks for the help
 
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ace123 said:
If you stand on a bathroom scale, spring inside compresses .6mm, and tells your weight is 710 N. Now if you jump on the scale from a height of 1m, what does the read at it's peak?

This is what I tried to do:

I used Hooke's law: F[tex]_{}s[/tex]= k*x
and solved for the k which is spring constant.

Then I wasn't too sure of how to find the spring compression when he jumps from a height of 1m. I tried to use conservation of mechanical energy:

I did the potential energy of the the guy at 1m and set it equal to the kinetic energy when he hits the scale.

I then set up another conservation of mechanical energy for the scale. Which was Kinetic energy equal to the compression 1/2kx^2.

This is wrong however and I have no clue what else to try.

Thanks for the help
Your method seems correct to me, however there is no need for the intermediate step you can just jump straight to setting the gravitational potential energy equal to the potential energy stored in the spring.

Note however, that the question asks for the reading on the scale, not the compression of the spring.
 
I understand that so after I find the compression of the spring i should multiply it by the spring constant. Correct? I threw in the intermediate step because I wasn't sure if you could jump from the gravitational potential energy straight to the spring.
 
Prehaps I made a mathematical mistake. Let me check it again.
 
ace123 said:
I understand that so after I find the compression of the spring i should multiply it by the spring constant. Correct?
That is correct. In that case, it is most likely that you have made an arithmetic error; or if you are submitting your answer online your significant figures are out.
 
Well the answer in the book is 4.2*10^4. But I'm not getting that. Can you check my math when I post it? Thanks
 
ace123 said:
Well the answer in the book is 4.2*10^4. But I'm not getting that. Can you check my math when I post it? Thanks
No problem :smile:
 
Wow you will not believe what I did. I thought .6mm was .6*10^-5. Got it confused with micro. Sorry for bothering you.:smile:
 
ace123 said:
Wow you will not believe what I did. I thought .6mm was .6*10^-5. Got it confused with micro. Sorry for bothering you.:smile:
It usually is the small mistakes that trip you up! Don't worry about it.
 

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