What Does It Cost to Use Electrical Appliances in Different Scenarios?

[wanted1]

1 - How much dose it cost in one month to burn a 2000 w room heater for 8h per day if electrical cost 10 Baiza per kwh ?

p = 2000
= 2000/1000 = 2.0 kw

E = pt
= (2.0) ( 8)
= 48.0

cost = 48.0 X 10 = 480.0

2 - Descibe the nature of the graphs for the satandaed resistor and the lamp ?
standard resistor is designed to be as ohmic as possible, meaning it will have a nearly perfectly linear current-voltage relationship over a large range of applied voltage. The slope of the I versus V curve in the linear region yields a value for R.


3 -The cost of electrical energy is 10 Bz/kwh. Calculate the cost of
a) leaving a 100-W porch light on for two weeks while you are on vacation
b) making a piece of dark toast in 3.0 min with a 750-W toaster , and in drying a load of clothes in 5 min with a 4500-W dayer

a = 336
b = 3/8
c = 15/4

 

[G01]

Your reasoning is fine, but you've made some calculation errors:

1. That the cost for one day, not for one month.

3.a)Correct

3.b)Also Correct.

3c)Correct, too.

Sorry, I did forget to multiply by 10B/kWh!

 

[Lame One]

I agree with G01 on the first error. The second, however, I'm not so sure about his evaluation of number 3 part B. I received the same answer as you after doing the math multiple times. G01, are you sure that you multiplied by the 10 kwh? Not sure if that's it, but there's something off. Same for part C. Again, not positive, but fairly certain.

 

[wanted1]

a do agine I get

a = 336
b = 3/8
c = 15/4

why??

what about Q 2
2 - Descibe the nature of the graphs for the satandaed resistor and the lamp ?
standard resistor is designed to be as ohmic as possible, meaning it will have a nearly perfectly linear current-voltage relationship over a large range of applied voltage. The slope of the I versus V curve in the linear region yields a value for R.

is correct ?

Q1

for one month. we do
160 X 30 = 4800

 

[G01]

I agree with G01 on the first error. The second, however, I'm not so sure about his evaluation of number 3 part B. I received the same answer as you after doing the math multiple times. G01, are you sure that you multiplied by the 10 kwh? Not sure if that's it, but there's something off. Same for part C. Again, not positive, but fairly certain.

Yeah, that'd be it!

Sorry, errors fixed.

To the OP:

For question 1, your answer is correct for one day, just multiply by the number of days in a month.

For question2, you're not actually comparing a resistor to a lamp bulb as the question asks.

 

[Lame One]

Yeah, that's kinda why I skipped the second question as well. You sort of made it sound like a graph or something was given, and you just threw the question at us.