What Does LIM Mean in Physics?

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SUMMARY

The acronym "LIM" in physics refers to "limit," particularly in the context of calculus. The formula presented, a = lim * delta(v) / delta(t), illustrates the relationship between acceleration and the limit of velocity change over time. This discussion highlights the foundational role of limits in understanding motion and calculus principles. For further clarity, the topic is suggested to be moved to a basic calculus forum for more in-depth exploration.

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  • Basic understanding of calculus concepts, specifically limits.
  • Familiarity with the relationship between speed, velocity, and acceleration.
  • Knowledge of mathematical notation and terminology.
  • Access to calculus resources, such as Wikipedia or academic textbooks.
NEXT STEPS
  • Study the concept of limits in calculus, focusing on its applications in physics.
  • Learn about the derivative and its relationship to acceleration using limits.
  • Explore the implications of limits in real-world physics problems.
  • Review basic calculus resources, including online courses or textbooks.
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Students of physics, educators teaching calculus, and anyone interested in the mathematical foundations of motion and acceleration.

Morchelloo
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What does LIM means in Physics..?
 
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You're going to have to give some context...
 
ok

IF a = speed than: a=lim*delta(v)/delta(t).

sorry for that, i haven't so many time and i am noobie to this forum. i register here few min ago so i just learning how everithing is moving here...

thanks for help!
 
Last edited:
This is basic calc and I'm moving this thread there.

Zz.
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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