1. The problem statement, all variables and given/known data Given a graph with distance (in meters) on the y axis and time (in seconds) on the x axis what does the area under this graph illustrate ? The object has a velocity of 1m/s so after 5 s it has travelled 5m. 2. Relevant equations This is a linear line (i.e y=x) so the area can be calculated based on that of a right angled triangle ( 1/2 base x height) 3. The attempt at a solution So using the time of 5 seconds, we have a triangle area of 1/2(5s)* 5m = 12.5 I'm unsure what these units would be ?? m/s ?? I didn't think it would be m/s as this is velocity and the velocity of the object is 1m/s. The area under graph , I don't believe to be acceleration, as to get acceleration from the area under a graph I'd need to have velocity on the y axis and time on the x axis....or wait would velocity on the y and time on the x give me displacement ??? I have distance in m on the y axis and time in s on the x axis. I know I can calculate velocity at specific points on the graph but don't understand what the area under a distance vs time graph would show.