- #1
urbano
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Homework Statement
Given a graph with distance (in meters) on the y-axis and time (in seconds) on the x-axis what does the area under this graph illustrate ?
The object has a velocity of 1m/s so after 5 s it has traveled 5m.
Homework Equations
This is a linear line (i.e y=x) so the area can be calculated based on that of a right angled triangle ( 1/2 base x height)
The Attempt at a Solution
So using the time of 5 seconds, we have a triangle area of 1/2(5s)* 5m = 12.5
I'm unsure what these units would be ?? m/s ?? I didn't think it would be m/s as this is velocity and the velocity of the object is 1m/s.
The area under graph , I don't believe to be acceleration, as to get acceleration from the area under a graph I'd need to have velocity on the y-axis and time on the x axis...or wait would velocity on the y and time on the x give me displacement ?
I have distance in m on the y-axis and time in s on the x axis.
I know I can calculate velocity at specific points on the graph but don't understand what the area under a distance vs time graph would show.