What does the integration variable t represent in the gamma function definition?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
Tiiba
Messages
53
Reaction score
0
The definition of this function is
Gamma(z) = integral(0, inf)(t^(z-1)e^(-t) dt)

Well, I can't understand what the t stands for. The only parameter is z... Is it an arbitrary number?
 
Physics news on Phys.org
Your integrand is a function of TWO variables:
[tex]f(z,t)=t^{z-1}e^{-t}[/tex]
When you integrate f(z,t) over the t-domain, ([tex]0\leq{t}<\infty[/tex]) , what you are left with, is a function of z alone:
[tex]\Gamma(z)=\int_{0}^{\infty}f(z,t)dt[/tex]
 
I think I get it. Thanks.