- #1
AJKing
- 104
- 2
Answered this myself as I wrote it.
Eight bricks, each 6.0 cm thick with a mass of 1.5 kg, lie flat on a table. How much work is required to stack them one on top of another?
hbrick = 0.060 m
m = 1.5 kg
W = Fd
Fg = m*g
I tried the following, and was correct. Please read the fourth point for my question.
Fg = 1.5*9.8 = 14.7 N
Wt = W1+W2+W3+W4+W5+W6+W7+W8
Wt = 14.7*0 + 14.7*.06 + . . . + 14.7*0.42 = 25 J4. My question
The answer to the question goes a little something exactly like this:
Where did that 3.5 come from?
7 bricks lifted divided by 2? Oh . . . Probably. Yeah. Averages and what not.
Writing this helped. Might as well post it.
Homework Statement
Eight bricks, each 6.0 cm thick with a mass of 1.5 kg, lie flat on a table. How much work is required to stack them one on top of another?
hbrick = 0.060 m
m = 1.5 kg
Homework Equations
W = Fd
Fg = m*g
The Attempt at a Solution
I tried the following, and was correct. Please read the fourth point for my question.
Fg = 1.5*9.8 = 14.7 N
Wt = W1+W2+W3+W4+W5+W6+W7+W8
Wt = 14.7*0 + 14.7*.06 + . . . + 14.7*0.42 = 25 J4. My question
The answer to the question goes a little something exactly like this:
8 bricks each with m = 1.5 kg
height of each brick h= 0.060m
centre of mass is lifted 3.5 h
W = (8*1.5*9.8)(3.5*0.060) = 25 J
Where did that 3.5 come from?
7 bricks lifted divided by 2? Oh . . . Probably. Yeah. Averages and what not.
Writing this helped. Might as well post it.