What does this value represent in this work question?

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SUMMARY

The discussion focuses on calculating the work required to stack eight bricks, each with a thickness of 6.0 cm and a mass of 1.5 kg. The total work done is derived using the formula W = Fd, where the force (Fg) is calculated as 14.7 N. The final calculation for work (Wt) is confirmed to be 25 J, with the center of mass being lifted an average height of 3.5 times the height of a single brick. The value of 3.5 arises from the average height of the bricks stacked, specifically calculated as the sum of the heights of the bricks divided by the number of bricks lifted.

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Answered this myself as I wrote it.

Homework Statement



Eight bricks, each 6.0 cm thick with a mass of 1.5 kg, lie flat on a table. How much work is required to stack them one on top of another?

hbrick = 0.060 m
m = 1.5 kg

Homework Equations



W = Fd
Fg = m*g

The Attempt at a Solution



I tried the following, and was correct. Please read the fourth point for my question.

Fg = 1.5*9.8 = 14.7 N

Wt = W1+W2+W3+W4+W5+W6+W7+W8

Wt = 14.7*0 + 14.7*.06 + . . . + 14.7*0.42 = 25 J4. My question

The answer to the question goes a little something exactly like this:

8 bricks each with m = 1.5 kg
height of each brick h= 0.060m
centre of mass is lifted 3.5 h

W = (8*1.5*9.8)(3.5*0.060) = 25 J

Where did that 3.5 come from?

7 bricks lifted divided by 2? Oh . . . Probably. Yeah. Averages and what not.

Writing this helped. Might as well post it.
 
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Yep. Your calculation is
W_t = 1.5 \times 9.81 \times (0.06 \times 0 + 0.06 \times 1 + \cdots + 0.06 \times 7)
Since (1 + 2 + ... + n) = 1/2 * n * (n + 1), you get (note that n = 7 in your case):
W_t = 1.5 \times 9.81 \times \frac{1}{2} \times 8 \times 7
which you can re-order to give the expression you had.
 

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