What does this value represent in this work question?

In summary, the question asks for the amount of work required to stack eight bricks on top of each other. Each brick has a mass of 1.5 kg and a height of 0.060 m. By using the formula W = Fd and the gravitational force equation Fg = m*g, it is determined that the total work required is 25 J. The formula used is W = (8*1.5*9.8)(3.5*0.060), where the 3.5 represents the average height of the centre of mass of the stacked bricks. This is based on the fact that the sum of the numbers from 1 to n can be expressed as 1/2*n*(n+
  • #1
AJKing
104
2
Answered this myself as I wrote it.

Homework Statement



Eight bricks, each 6.0 cm thick with a mass of 1.5 kg, lie flat on a table. How much work is required to stack them one on top of another?

hbrick = 0.060 m
m = 1.5 kg

Homework Equations



W = Fd
Fg = m*g

The Attempt at a Solution



I tried the following, and was correct. Please read the fourth point for my question.

Fg = 1.5*9.8 = 14.7 N

Wt = W1+W2+W3+W4+W5+W6+W7+W8

Wt = 14.7*0 + 14.7*.06 + . . . + 14.7*0.42 = 25 J4. My question

The answer to the question goes a little something exactly like this:

8 bricks each with m = 1.5 kg
height of each brick h= 0.060m
centre of mass is lifted 3.5 h

W = (8*1.5*9.8)(3.5*0.060) = 25 J

Where did that 3.5 come from?

7 bricks lifted divided by 2? Oh . . . Probably. Yeah. Averages and what not.

Writing this helped. Might as well post it.
 
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  • #2
Yep. Your calculation is
[tex]W_t = 1.5 \times 9.81 \times (0.06 \times 0 + 0.06 \times 1 + \cdots + 0.06 \times 7)[/tex]
Since (1 + 2 + ... + n) = 1/2 * n * (n + 1), you get (note that n = 7 in your case):
[tex]W_t = 1.5 \times 9.81 \times \frac{1}{2} \times 8 \times 7[/tex]
which you can re-order to give the expression you had.
 

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