Give example of matrices such that AB=AC but B=/=C

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Homework Help Overview

The discussion centers around finding examples of 2 x 2 matrices A, B, and C such that the product of A with B equals the product of A with C (AB = AC), while B and C are not equal. This is a problem within the subject area of linear algebra, specifically dealing with matrix multiplication and properties of matrices.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of matrix A being invertible and how that affects the equality AB = AC. There are attempts to identify specific matrices that satisfy the conditions of the problem, with some participants questioning the nature of the zero matrix and its role in the discussion.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some have suggested specific forms for matrices A, B, and C, while others are questioning the assumptions about matrix A's invertibility. There is no explicit consensus, but productive lines of reasoning are being explored.

Contextual Notes

Participants note that A must not be invertible for the condition AB = AC to hold while B and C remain distinct. The discussion also touches on the definition of the zero matrix and its implications in the context of the problem.

xlalcciax
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1. Let M(2,R) be the set of all 2 x 2 matrics over R. Give an example of matrices A,B,C in M(2,R) such that AB=AC, but B is not equal to C.


3.
 
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xlalcciax said:
1. Let M(2,R) be the set of all 2 x 2 matrics over R. Give an example of matrices A,B,C in M(2,R) such that AB=AC, but B is not equal to C.


3.
What have you tried? You have to show some effort before we can provide any help.
 


Mark44 said:
What have you tried? You have to show some effort before we can provide any help.

(A^-1)AB=(A^-1)AC so B=C. This shows that A must have no inverse element. So A could be
1 0
0 0
because det(a)=1-0=0 so A has no inverse. I don't know what A and B could be.
 


xlalcciax said:
(A^-1)AB=(A^-1)AC so B=C. This shows that A must have no inverse element.
No, what this shows is that if A is invertible (has an inverse), then AB = AC implies that B = C. But you're not given that A is invertible.
xlalcciax said:
So A could be
1 0
0 0
because det(a)=1-0=0 so A has no inverse. I don't know what A and B could be.
You mean B and C. See if you can cobble up different matrices B and C so that AB = 0 and AC = 0, but B != C.
 


Mark44 said:
No, what this shows is that if A is invertible (has an inverse), then AB = AC implies that B = C. But you're not given that A is invertible.

You mean B and C. See if you can cobble up different matrices B and C so that AB = 0 and AC = 0, but B != C.

what does AB = 0 mean? does it mean det(A) x det(B) or matrix A x matrix B?
 


By 0 I meant the 2 x 2 matrix whose entries are all 0.
 


Mark44 said:
By 0 I meant the 2 x 2 matrix whose entries are all 0.

so they could be B = 0 0 and C = 0 0 ??
...... 0 1....1 0
 


Sure, why not? All you had to do was come up with three 2 x 2 matrices such that AB = AC, but B != C. It looks like you did just what you are asked to do.
 

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