What Force is Required to Hold Up a Partner on a Swinging Circle?

[spidey12]

Homework Statement

A man hanging upside down is holding a partner who weighs 565 N. Assume that the partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.40 m/s, what force must the man apply to his partner in the straight-down position?

Homework Equations

I'm at a loss.

The Attempt at a Solution

but I am pretty sure that at the bottom of the circle the man holding up the other man must hold up a force=mg where m is the mass of the bottom partner. Therefore F=565.

Am I being asked the centripedial force?

I tried F(centripedal)= (525/9.8)*(4.4)² and then divide that by the radius 6.5.

I got 160 which is not the correct answer.

 

[rock.freak667]

The upside-down man exerts an upward force towards the centre of the circle. The weight of his partner is downwards. The resultant of those 2 forces provides the centripetal force needed to make him move at that speed.

 

[spidey12]

The upside-down man exerts an upward force towards the centre of the circle. The weight of his partner is downwards. The resultant of those 2 forces provides the centripetal force needed to make him move at that speed.

I keep getting 160 :(

Fc=mv²/r

Is that not correct?

 

[spidey12]

I keep getting 160 :(

Fc=mv²/r

Is that not correct?

Ok. I solved it. Thanks to the one person who helped me.