Finding the Force Applied to a Partner Swinging at 4.25 m/s

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SUMMARY

The discussion focuses on calculating the force required by a man to support his partner swinging at a speed of 4.25 m/s on a circular path with a radius of 6.50 m. The partner's weight is given as 570 N. The initial calculation attempts to use the formula for centripetal force, Fc = (mv^2)/r, resulting in an estimated force of 1580 N. The calculation requires verification and clarification of the applied physics principles.

PREREQUISITES
  • Understanding of centripetal force and its formula, Fc = (mv^2)/r
  • Basic knowledge of weight and gravitational force
  • Familiarity with units of force (Newtons)
  • Ability to perform algebraic calculations involving variables
NEXT STEPS
  • Review the concept of centripetal acceleration and its relationship to circular motion
  • Learn about the forces acting on objects in circular motion
  • Explore examples of force calculations in physics problems
  • Investigate the implications of angular velocity in circular motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of force calculations in real-world applications.

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Homework Statement



In the figure the man hanging upside down is holding a partner who weighs 570 N. Assume that the partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.25 m/s, what force must the man apply to his partner in the straight-down position?
p5-46.gif

Homework Equations


Fc=(mv^2)/(t)

The Attempt at a Solution


(570*(4.25)^2) / 6.5

1580 n?

If my logic is wrong, please tell me.
 
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