What Force is Required to Hold Up a Partner on a Swinging Circle?

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Homework Help Overview

The problem involves a scenario where a man is holding his partner, who weighs 565 N, while they are moving in a circular path with a radius of 6.50 m at a speed of 4.40 m/s. The focus is on determining the force required to hold up the partner in a straight-down position.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between the forces acting on the partner, including gravitational force and centripetal force. There are attempts to calculate the necessary force using the formula for centripetal force, with some expressing confusion about the correct approach.

Discussion Status

Some participants are exploring different interpretations of the forces involved, particularly the relationship between the weight of the partner and the centripetal force required for circular motion. There is mention of a potential resolution by one participant, but no explicit consensus has been reached on the correct method or answer.

Contextual Notes

Participants are grappling with the definitions and roles of the forces at play, particularly in the context of circular motion and the specific scenario described. There is an indication of uncertainty regarding the calculations and assumptions made.

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Homework Statement


A man hanging upside down is holding a partner who weighs 565 N. Assume that the partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.40 m/s, what force must the man apply to his partner in the straight-down position?

Homework Equations



I'm at a loss.

The Attempt at a Solution



but I am pretty sure that at the bottom of the circle the man holding up the other man must hold up a force=mg where m is the mass of the bottom partner. Therefore F=565.

Am I being asked the centripedial force?

I tried F(centripedal)= (525/9.8)*(4.4)2 and then divide that by the radius 6.5.

I got 160 which is not the correct answer.
 
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The upside-down man exerts an upward force towards the centre of the circle. The weight of his partner is downwards. The resultant of those 2 forces provides the centripetal force needed to make him move at that speed.
 
rock.freak667 said:
The upside-down man exerts an upward force towards the centre of the circle. The weight of his partner is downwards. The resultant of those 2 forces provides the centripetal force needed to make him move at that speed.

I keep getting 160 :(

Fc=mv2/r

Is that not correct?
 
spidey12 said:
I keep getting 160 :(

Fc=mv2/r

Is that not correct?

Ok. I solved it. Thanks to the one person who helped me.
 

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