What Forces Act on a Train Engine Going Around a Circular Curve?

Click For Summary
SUMMARY

The discussion centers on the forces acting on a train engine navigating a circular curve, emphasizing the importance of the normal force exerted by the rails on the wheels. Participants clarify that the free body diagram should depict the gravitational force (mg) acting downward, the normal force (N) acting upward, and the net centripetal force (F) directed towards the center of the curve. The conversation also highlights the significance of the wheel's rim in maintaining the train's trajectory and preventing derailment, particularly when the train is turning.

PREREQUISITES
  • Understanding of Newton's Second Law
  • Knowledge of circular motion principles
  • Familiarity with free body diagrams
  • Basic concepts of forces and motion in physics
NEXT STEPS
  • Study the mechanics of circular motion in depth
  • Learn how to construct free body diagrams for various scenarios
  • Explore the role of friction and normal forces in motion
  • Investigate the effects of speed on train stability during turns
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of trains and circular motion mechanics.

Kernul
Messages
211
Reaction score
7

Homework Statement


A train engine of mass ##m## is chugging its way around a circular curve of radius ##R## at a constant speed ##v##. Draw a free body/force diagram for the train engine showing all of the forces acting on it.
Evaluate the total vector force acting on the engine as a function of its speed in a plane perpendicular to its velocity ##\vec v##.
You may find the picture of the train’s wheels useful. Note that they are notched so that they fit onto the rails – the thin rim of metal that rides on the inside of each rail is essential to the train being able to go around a curve and stay on a track!
Draw a schematic picture of the wheel and rail in cross-section and draw in the forces using the force rules we have learned so far that illustrate how a rail can exert both components of the force needed to hold a train up and curve its trajectory around in a circle.
Discussion: What is the mechanical origin of the force responsible for making the train go in a curve without coming off of the track (and for that matter, keeping it on the track in the first place, even when it is going “straight”)? What would happen if there were no rim on the train’s wheels?
Immagine.png


Homework Equations


Newton's Second Law
Circular Motion

The Attempt at a Solution


This is the free body diagram I drew:
photo_2016-12-22_18-42-21.jpg

But besides this, I don't know what are the forces that are actually acting on the train. Can someone guide me through the exercise?
And about drawing a schematic picture of the wheel and rail in cross-section, I didn't quite get how I should do that.
 
Physics news on Phys.org
That drawing shows an x and a y axis. What are x and y? Are we looking down at the track from above so that x is east and y is north? Or are we looking at the train from the rear so that x is right and y is up?

The drawing shows a leftward F. What force is that?
The drawing shows an upward "v", "q" or backwards "g" with a minus sign in front. What force is that?

The drawing shows R. A free body diagram is supposed to show forces. What forces act on the train engine?
 
jbriggs444 said:
That drawing shows an x and a y axis. What are x and y? Are we looking down at the track from above so that x is east and y is north? Or are we looking at the train from the rear so that x is right and y is up?
Kernul said:
A train engine of mass ##m## is chugging its way around a circular curve of radius ##R## at a constant speed ##v##. Draw a free body/force diagram for the train engine showing all of the forces acting on it.
So the problem actually asked me to draw the curve seen from above.

jbriggs444 said:
The drawing shows a leftward F. What force is that?
That's the net force pointing to the center of the circular curve.

jbriggs444 said:
The drawing shows an upward "v", "q" or backwards "g" with a minus sign in front. What force is that?
It's a "v", since the problem was talking about that, and it's a velocity.

jbriggs444 said:
The drawing shows R. A free body diagram is supposed to show forces. What forces act on the train engine?
The "R" is the radius of the circular curve.

I wrote these last two just to show how I see the problem.
 
Kernul said:
So the problem actually asked me to draw the curve seen from above.
A "free body diagram" is a diagram that shows all forces acting on a body. The problem does not ask for a curve seen from above.
 
  • Like
Likes   Reactions: Kernul
jbriggs444 said:
A "free body diagram" is a diagram that shows all forces acting on a body. The problem does not ask for a curve seen from above.
Oh my... you're right. What was I even trying to do there?

Anyway, from what prospective should I draw the free body diagram?
If I write it from the top of the train, wouldn't I have just one force pointing to the center of the curve?
If I write it from the rear of the train, I would have the gravity force ##mg## going down and the normal force ##N## going up, with, again, a force ##F## going to the side because of the centrifugal acceleration. (For example the negative side of the x-axis)
 
Kernul said:
Anyway, from what prospective should I draw the free body diagram?
If I write it from the top of the train, wouldn't I have just one force pointing to the center of the curve?
If I write it from the rear of the train, I would have the gravity force ##mg## going down and the normal force ##N## going up, with, again, a force ##F## going to the side because of the centrifugal acceleration. (For example the negative side of the x-axis)

I like the way you are thinking here.

As you say, if you look down from the top, you will not be able to present the downward force of gravity or the upward normal force. If you look forward from the train's rear you will be able to present both of those forces easily.

A free body diagram is mainly an aid to understanding. It is a graphical presentation that forces you do identify all of the forces on an object. Let us go back to the problem statement and see what forces will be important...

Kernul said:
Draw a schematic picture of the wheel and rail in cross-section and draw in the forces using the force rules we have learned so far that illustrate how a rail can exert both components of the force needed to hold a train up and curve its trajectory around in a circle.

As I read it, the free body diagram is going to be a rough outline which gets made more specific by this schematic. So you need the free body diagram to be from the same perspective as the schematic. A "cross section".

That is to say, a view from the rear, looking at engine and rails end-on.
 
jbriggs444 said:
As I read it, the free body diagram is going to be a rough outline which gets made more specific by this schematic. So you need the free body diagram to be from the same perspective as the schematic. A "cross section".

That is to say, a view from the rear, looking at engine and rails end-on.
So I have to draw the rails and wheels and write the forces acting between the two? All this in the same drawing looking at the train engine from the rear?
Does it stays on track because the rails exert a normal force on the wheels, specifically on the rim of metal?
 
Kernul said:
So I have to draw the rails and wheels and write the forces acting between the two? All this in the same drawing looking at the train engine from the rear?
For the free body diagram, concentrate on the engine. All you are concerned with is the forces acting on the engine. You would not want to get into details of the wheels. When you get to the schematic, you are asked to focus in more on the details.

I see it as two drawings. One crude and one with more details.
Does it stays on track because the rails exert a normal force on the wheels, specifically on the rim of metal?
You use the term "normal force". What do you mean by that in this context? How would you say that it explains how the train stays on the track?
 
jbriggs444 said:
For the free body diagram, concentrate on the engine. All you are concerned with is the forces acting on the engine. You would not want to get into details of the wheels. When you get to the schematic, you are asked to focus in more on the details.

I see it as two drawings. One crude and one with more details.
photo_2016-12-22_23-24-07.jpg

This would be the diagram from the rear.

jbriggs444 said:
You use the term "normal force". What do you mean by that in this context? How would you say that it explains how the train stays on the track?
This is what I mean:
photo_2016-12-22_23-24-12.jpg

This happens anytime the train engine turns. Or, to better say, when the rails change course, and so they "curve". When they curve, they basically exert a force on the rim of metal at the end of the wheel while at the same time the wheel exerts a force on it too.
photo_2016-12-22_23-24-09.jpg

This case, instead, makes the train engine derail because of no opposition of the rail. (No rim of metal, no force on the wheel, and so train goes on the side without any force opposing it)
 
  • #10
On the free body diagram, you showed a vertical force of rail on engine. On the detailed diagram, that force is absent. The "normal" force you depict is not perpendicular to anything. Where is the vertical supporting force?

On the final drawing, you speak of a "force applied by the wheel but without opposition of the rail". What does Newton's third law have to say about that concept?
 
  • #11
I think your FBD is slightly too simple. Can I point out that there are two rails so I would expect more than one vertical force acting on the train (unless the train was going dangerously fast!).
 

Similar threads

Replies
19
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
55
Views
3K
  • · Replies 12 ·
Replies
12
Views
990
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
6
Views
4K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 12 ·
Replies
12
Views
3K