What forces are acting on an object during a bounce?

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Homework Help Overview

The discussion revolves around the forces acting on an object, specifically a wrench, during a bounce. Participants explore concepts related to free body diagrams and the implications of forces such as weight and normal force, as well as the concept of impulse in the context of motion and torque.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the importance of free body diagrams and the need to identify the location of forces acting on the object. Questions arise regarding the completeness of the identified forces and their relation to torque during the bounce.

Discussion Status

The discussion is ongoing, with participants examining the forces involved and their effects on the object's motion. Some guidance has been provided regarding the significance of showing force locations on diagrams and considering rotational effects, but no consensus has been reached on the complete analysis of the forces.

Contextual Notes

There is an emphasis on understanding the dynamics of the situation, including the role of impulse and torque, but some participants express uncertainty about the completeness of their diagrams and analyses.

Jeff97
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Homework Statement
While I was placing a spanner on the bonnet of a car it slips out of my hand
and falls to the ground.

On this diagram can you show me (draw) vectors showing the
force(s) acting on the spanner at the
instant it hits the ground. Label the forces.
Relevant Equations
N/a
Screenshot 2019-08-07 at 7.54.28 AM.png
This is not a homework question. I merely am interested in what forces are acting on it.
 
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Even if it's not homework, you can still take a cut at the solution. Start with a free body diagram (FBD) of the wrench and show the force(s) on it just as it makes contact with the ground. Also, are you familiar with the concept of "impulse"?
 
@berkeman No, I didn't know " impulse is the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector in the same direction. Impulse applied to an object produces an equivalent vector change in its linear momentum, also in the same direction." Got it now. I drew one. All the forces I got was Weight (mg) downwards and Fn (normal force upwards)
 
Yes, there are two forces one up and the other down but that is not enough. Where, on the spanner, did you draw them as acting?
 
I didn't, really.
 
Jeff97 said:
I didn't, really.
So on FBDs, it's important to show where the forces are acting, and how that relates to any torques on the object. In this case, the force of hitting the ground (the impulse over the short bounce time) will produce a torque that causes a rotation as part of the bounce. Also, if the wrench was rotating when it hit the ground, that will affect the overall motion.
 

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