What Formula is Needed to Find the Capacitor Value for a Half Wave Rectifier?

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SUMMARY

The formula required to calculate the capacitor value for a half-wave rectifier is V_r = I_dc / (f * C), where V_r is the ripple voltage, I_dc is the direct current, f is the frequency of the supply voltage, and C is the capacitance. In this scenario, with a load current of 100 mA and an input frequency of 60 Hz, the goal is to limit the ripple to 160 mVpp. Understanding this formula is essential for accurately determining the necessary capacitor value in rectifier circuits.

PREREQUISITES
  • Basic understanding of electrical circuits
  • Knowledge of half-wave rectifier operation
  • Familiarity with ripple voltage concepts
  • Ability to perform calculations involving capacitance
NEXT STEPS
  • Research "half-wave rectifier capacitor filter" for detailed explanations
  • Study the impact of load current on ripple voltage
  • Learn about capacitor selection criteria in power supply design
  • Explore the effects of frequency on rectifier performance
USEFUL FOR

Electrical engineering students, hobbyists designing power supplies, and professionals working with rectifier circuits will benefit from this discussion.

snowJT
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Homework Statement



A half wave rectifier is supplying a load current of 100 mA. The input frequency is 60 Hz. Find the capacitor value required to limit the ripple ot 160 mVpp.

Really... I can solve this I'm sure... But I'm wondering what formula I need to use... I've never been shown one in class, and I don't have a textbook, so a little help with a formula would be nice...
 
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its V = IR
 
somebody please?
 
I think the equation you're looking for is V_r=I_{dc}/fC.
Where Vr is the ripple voltage, Idc is the direct current, f is the frequency of the supply voltage, and C is the capacitance. But I would do a search for something like "half-wave rectifier capacitor filter" to learn about it and be sure that you agree with it. OK? I don't want to mislead you.
 

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