L1. The problem statement, all variables and given/known data A Transformer with a stepdown ratio of 10:1 is supplied with a 230 RMS voltage at 50hz connected to a four diode full wave bridge rectifier and smoothing circuit. If the smoothing capacitor value is 1000uF and the load resistance RL is 25 ohms, find: the secondary winding rms and peak voltage, the peak voltage across the capacitor the peak to peak and rms ripple voltages the load dc voltage and current 2. Relevant equations 3. The attempt at a solution Ok the peak secondary winding voltage is 23V +1.4V(assuming 2 diodes at 0.7v each)=24.4V The secondary rms is 24.4/sqrt2= 17.253V Peak capacitor voltage VCP is secondary rms - 1.4V = 17.253-1.4= 15.853V Peak to Peak ripple voltage is VRPP= (1/(2fCRL))(VCP-(VRPP/2). Solving for VRPP, VRPP=0.4(15.853-VRPP/2), VRPP=5.28V RMS ripple voltage VR(RMS) is 5.28/(2*3sqrt)= 1.52V DC load voltage is VCP - (VRPP/2) = 15.853 - (5.28/2)= 13.213V Load Current IL is VL/RL= 13.213/25= 0.528A Can someone verify the methods I have used.