What Happens When the Tension in a Musical Instrument String is Doubled?

Click For Summary
SUMMARY

The discussion focuses on the effects of doubling the tension in a string of a newly designed musical instrument, which consists of a metal tube and a string with mass per unit length μ. The tension is initially calculated as vsound²μ/60. When the tension is doubled, the frequency of the standing wave on the string increases, resulting in a higher pitch sound. The participants also explore the resonance of other harmonics in the string with the air column in the tube, emphasizing the relationship between tension, frequency, and pitch.

PREREQUISITES
  • Understanding of wave mechanics, specifically standing waves.
  • Knowledge of tension in strings and its effect on frequency.
  • Familiarity with the speed of sound in air and its relation to musical instruments.
  • Basic equations of harmonics, particularly ƒn=nv/2L.
NEXT STEPS
  • Research the relationship between tension and frequency in stringed instruments.
  • Learn about the harmonic series and resonance in musical acoustics.
  • Explore the effects of varying tension on pitch in string instruments.
  • Study the principles of wave propagation in different mediums, including air and strings.
USEFUL FOR

Musicians, acoustics engineers, physics students, and anyone interested in the mechanics of musical instruments and sound production.

Sky07
Messages
1
Reaction score
0
Hello, I am having a hard time solving this question. Any help is really appreciated.

1. Homework Statement

You have designed a new musical instrument of very simple construction. Your design consists of a metal tube with length L and diameter L/10. You have stretched a string of mass per unit length μacross the open end of the tube. The other end of the tube is closed. To produce the musical effect you're looking for, you want the frequency of the third-harmonic standing wave on the string to be the same as the fundamental frequency for sound waves in the air column in the tube. The speed of sound waves in this air column is vs.

b)What happens to the sound produced by the instrument if the tension is changed to twice the value calculated . The tension is vsound^2μ/60?

c) For the tension calculated vsound^2μ/60, what other harmonics of the string, if any, are in resonance with standing waves in the air column?

Homework Equations


ƒn=nv/2L

The Attempt at a Solution


[/B]
B) for this part my idea is because tension is increasing the the frequency of the waves will increase as per the formula. However, I am unsure if the sound would become a higher pitch or lower pitch.
C) I am not really sure about this one.

Thank you for your help!
 
Last edited by a moderator:
Physics news on Phys.org
Sky07 said:
The tension is vsound^2μ/60?
That's the tension before it is doubled? I get something different - please post your working. However, it is only different by a constant factor, so shouldn't change the answer to b.
Sky07 said:
the frequency of the waves will increase as per the formula. However, I am unsure if the sound would become a higher pitch or lower pitch.
You don't know whether a higher frequency is a higher or lower pitch?
Sky07 said:
What happens to the sound produced by the instrument if the tension is changed to twice the value calculated
You're not told how the instrument is to be played, but presumably the idea is to pluck the string. You need to think on this very carefully: What will happen when you do that with the original design?
What will happen when you pluck the string with twice the tension?
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
31
Views
4K
Replies
20
Views
5K
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
7K