Connecting two batteries with their positive terminals together and negative terminals together results in no change in voltage or potential difference, provided both batteries have the same voltage. This configuration effectively places the batteries in parallel, maintaining the same voltage while doubling the amp-hour capacity. If connected in series (positive to negative), the batteries would drain quickly and could overheat the connecting wires. The discussion emphasizes the conceptual understanding of battery configurations and their implications on electrical properties.
PREREQUISITESStudents studying electrical engineering, hobbyists working with batteries, and anyone interested in understanding battery configurations and their effects on circuit performance.
Sounds reasonable. Are you possibly also supposed to make an observation about the properties of the resulting battery pair?CasterlyRock said:I quess that nothing happens because there is no voltage difference.
I meant properties of the pair after connection compared to a single battery. Volts? Amps? Amp-hour capacity?CasterlyRock said:No, it only says that batteries are the same.
Really nothing except what I wrote. The question has a conceptual nature. I assumed that when connected, batteries are in parallel, that means the same potential as it was, so nothing changes.insightful said:I meant properties of the pair after connection compared to a single battery. Volts? Amps? Amp-hour capacity?
I don't understand. Do you mean if I would apply a resistor to that new one battery (lets say a resistor is a lightbulb) it would shine brighter than one applied to the original battery?insightful said:Could you not say that you produced a "new" battery with the same volts, but twice the amp and amp-hour capacity?
Why would it shine brighter with the same volts applied?CasterlyRock said:I don't understand. Do you mean if I would apply a resistor to that new one battery (lets say a resistor is a lightbulb) it would shine brighter than one applied to the original battery?
No, I said the amp capacity is greater than before. How much greater?CasterlyRock said:P=I^2*R. You've said that amp is greater than before.