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## Homework Statement

In the attached file..

The question asks about the charge and capacitance after being separated by twice the original separation. I also need to know if it is kept connected to the battery( spearted to twice the distance,too) , what would happen to both the charge and capacitance? What would happen if the distance remained the same?

## Homework Equations

Capacitance is proportional to the area of the plates and inversely proportional to the distance between them.

C= charge/ potential difference

## The Attempt at a Solution

Well, if it disconnected from the battery, the charge will stay the same. However, the capacitance will be halved since the distance is doubled . Now, if it is kept connected, I think that because charge increases with increasing voltage, so it will keep attaining all the potential and then be constant; additionally, the capacitance is not changed if the distance remained the same, but it will be halved if the distance is doubled. So, capacitance is independent on the charge. Am I right?

#### Attachments

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