In the attached file..
The question asks about the charge and capacitance after being separated by twice the original separation. I also need to know if it is kept connected to the battery( spearted to twice the distance,too) , what would happen to both the charge and capacitance? What would happen if the distance remained the same?
Capacitance is proportional to the area of the plates and inversely proportional to the distance between them.
C= charge/ potential difference
The Attempt at a Solution
Well, if it disconnected from the battery, the charge will stay the same. However, the capacitance will be halved since the distance is doubled . Now, if it is kept connected, I think that because charge increases with increasing voltage, so it will keep attaining all the potential and then be constant; additionally, the capacitance is not changed if the distance remained the same, but it will be halved if the distance is doubled. So, capacitance is independent on the charge. Am I right?
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