The discussion revolves around the connection of two batteries with their positive terminals connected to each other and their negative terminals connected to each other. The subject area includes concepts of electrical circuits and battery properties.
The discussion is ongoing, with participants offering various interpretations of the effects of connecting batteries in this manner. Some guidance has been provided regarding the conceptual nature of the question, but no consensus has been reached on the specific outcomes or properties of the battery pair.
Participants note that the batteries are assumed to be of the same voltage, and there is a focus on understanding the implications of this assumption in relation to the properties of the connected batteries.
Sounds reasonable. Are you possibly also supposed to make an observation about the properties of the resulting battery pair?CasterlyRock said:I quess that nothing happens because there is no voltage difference.
I meant properties of the pair after connection compared to a single battery. Volts? Amps? Amp-hour capacity?CasterlyRock said:No, it only says that batteries are the same.
Really nothing except what I wrote. The question has a conceptual nature. I assumed that when connected, batteries are in parallel, that means the same potential as it was, so nothing changes.insightful said:I meant properties of the pair after connection compared to a single battery. Volts? Amps? Amp-hour capacity?
I don't understand. Do you mean if I would apply a resistor to that new one battery (lets say a resistor is a lightbulb) it would shine brighter than one applied to the original battery?insightful said:Could you not say that you produced a "new" battery with the same volts, but twice the amp and amp-hour capacity?
Why would it shine brighter with the same volts applied?CasterlyRock said:I don't understand. Do you mean if I would apply a resistor to that new one battery (lets say a resistor is a lightbulb) it would shine brighter than one applied to the original battery?
No, I said the amp capacity is greater than before. How much greater?CasterlyRock said:P=I^2*R. You've said that amp is greater than before.