What is a Measure with Finite Mass?

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A measure with finite mass refers to a measure where the total variation is finite, specifically denoted as |m|(Q) < infinity. This concept is distinct from sigma-finite measures, which allow for the measure to be infinite but still decomposable into countably many finite measures. The discussion highlights its application in functional analysis, particularly in the context of continuous functions on compact Hausdorff spaces. The relevance of this concept is illustrated through Peter Lax's text, where signed measures of finite total mass are utilized in defining bounded linear functionals. Understanding finite mass measures is essential for deeper insights into geometric measure theory and related mathematical frameworks.
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Quick question: what does it mean for a measure to have finite mass? (is this another way of saying sigma finite or something?)

Thanks,

Kevin
 
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Without context it is hard to say. However, it probably means that the measure of the set in question is finite.
 
I wonder if you've come across linear operators called m-currents recently? Is this a question from geometric measure theory?
 
Lonewolf said:
I wonder if you've come across linear operators called m-currents recently? Is this a question from geometric measure theory?

Not recently, I'm aware of currents and they're on my short list (as is GMT). However, the question over what "they" mean by a measure with finite mass has popped up in a couple places. But here's one:

I'm using Peter Lax's functional analysis text (very nice by the way) and amoung many uses here's one:

Th. 14: Let Q be a compact hausdorff space, C(Q) the space of continuous real-valued functions on Q, normed by the max norm.

(i) C' consists of all signed measures m of finite total mass, defined over all Borel sets. That is, every bounded linear functional L on C(q) can be written as

L(f)=Integral over Q of f dm
and so on and so forth...
 
Ok then. What it means is that the measure m has to satisfy |m|(Q) < infinity, where |m| is the total variation of the measure m. That help you any?
 
Yeah that helps, thanks.

kevin
 
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