What is acceleration due to gravity of earth?

Click For Summary
SUMMARY

The acceleration due to gravity at Earth's surface is approximately 9.80 m/s². However, when considering Earth's rotation, the centripetal acceleration at the equator is calculated to be 0.0337 m/s². This value represents a small fraction of gravitational acceleration, specifically 0.00344g. The calculations utilize the radius of Earth (6,380,000 m) and the rotational period (T = 86,400 s) to derive the centripetal acceleration.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula: Ar = v²/r
  • Familiarity with the concepts of rotational motion and inertial frames
  • Basic knowledge of gravitational acceleration and its measurement
  • Ability to perform calculations involving π and unit conversions
NEXT STEPS
  • Explore the effects of Earth's rotation on gravitational measurements
  • Learn about the differences between inertial and non-inertial reference frames
  • Investigate the implications of centripetal acceleration in various contexts
  • Study the relationship between radius, period, and acceleration in circular motion
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in the effects of Earth's rotation on gravitational forces.

6spdtls
Messages
2
Reaction score
0

Homework Statement


Earth is not quite an inertial frame. We often make measurements in a reference frame fixed on the Earth, assuming Earth is an inertial reference frame. But the Earth rotates, so this assumption is not quite valid.
Calculate the acceleration of an object at Earth's equator due to Earth's daily rotation, and compare to , the acceleration due to gravity.


Homework Equations


V=2πR/T -> Ar=v^2/r Ar=4π^2r/T^2
Radius of Earth: 6380000m; T=86400s


The Attempt at a Solution


When I plugged my value, Ar(centripetal acceleration) = 0.0337m/s^2
From here, what do I need to do?
 
Physics news on Phys.org
I got the answer already lol...it's 0.0337m/s^2 / 9.80m/s^2 = 0.00344g
 

Similar threads

Find g, measured to be 9.78 at the equator, when Earth is still
  • · Replies 17 ·
Replies
17
Views
2K
Gravitation sum related to Centripetal Acceleration
  • · Replies 5 ·
Replies
5
Views
3K
Is My Calculation of Centripetal Acceleration and Tangential Velocity Correct?
  • · Replies 12 ·
Replies
12
Views
2K
How fast should the Earth spin for centripital accel. to equal gravity?
  • · Replies 8 ·
Replies
8
Views
3K
Calculating Centripetal Acceleration at Earth's Equator
  • · Replies 1 ·
Replies
1
Views
2K
What is the Height of the International Space Station Above the Earth's Surface?
  • · Replies 2 ·
Replies
2
Views
4K
Constant acceleration in a rocket
  • · Replies 4 ·
Replies
4
Views
2K
Acceleration of Planet/Sun System
  • · Replies 3 ·
Replies
3
Views
2K
Maglev Train and Earth's Rotation
  • · Replies 7 ·
Replies
7
Views
2K
The acceleration due to gravity on the surface of the Earth is:
  • · Replies 2 ·
Replies
2
Views
2K