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What is acceleration due to gravity of earth?

  1. Feb 3, 2012 #1
    1. The problem statement, all variables and given/known data
    Earth is not quite an inertial frame. We often make measurements in a reference frame fixed on the Earth, assuming Earth is an inertial reference frame. But the Earth rotates, so this assumption is not quite valid.
    Calculate the acceleration of an object at Earth's equator due to Earth's daily rotation, and compare to , the acceleration due to gravity.


    2. Relevant equations
    V=2πR/T -> Ar=v^2/r Ar=4π^2r/T^2
    Radius of Earth: 6380000m; T=86400s


    3. The attempt at a solution
    When I plugged my value, Ar(centripetal acceleration) = 0.0337m/s^2
    From here, what do I need to do?
     
  2. jcsd
  3. Feb 3, 2012 #2
    I got the answer already lol.......it's 0.0337m/s^2 / 9.80m/s^2 = 0.00344g
     
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