What is band bending and how does it relate to Fermi Energy?

Click For Summary
SUMMARY

This discussion focuses on the concept of band bending in semiconductor physics, particularly in the context of a pn junction in silicon (Si) at 300K with doping concentrations of NA = 1021/m3 and ND = 1023/m3. The Fermi level (EF) is calculated using the equation Ne = NC e-(EG - EF)/(kBT). Band bending occurs due to the need for energy bands to align at the junction, which leads to charge carriers being trapped near the junction. The relationship between Fermi energy and band bending is expressed through equations involving EC, NC, and NV.

PREREQUISITES
  • Understanding of semiconductor physics, specifically pn junctions
  • Familiarity with Fermi energy calculations
  • Knowledge of energy band theory in semiconductors
  • Proficiency in using equations related to charge carrier concentrations
NEXT STEPS
  • Study the derivation of band bending in pn junctions using energy band diagrams
  • Learn about the impact of doping concentrations on Fermi level and band bending
  • Explore the relationship between charge carrier concentrations and band bending
  • Investigate the role of temperature in semiconductor behavior and band bending
USEFUL FOR

Students and professionals in semiconductor physics, electrical engineering, and materials science, particularly those studying pn junctions and their electrical properties.

HunterDX77M
Messages
42
Reaction score
0

Homework Statement


Consider a pn junction in Si at 300K (other parameters given), with doping NA = 1021/m3 and ND = 1023/m3. Assume all impurities are ionized. On this basis find the Fermi level on each side. From this find the band bending VB and make a sketch of the pn junction.

Homework Equations


N_e = N_C e^{\frac{-(E_G - E_F)}{k_B T}}


The Attempt at a Solution


The Fermi energy calculation was fairly straightforward to solve for, since I just used the formula above for both sides and solved for EF. My question is about band bending. What is it and how do I calculate it? I looked through the relevant chapter in my text-book, but I couldn't find any reference to it. Can someone show me how it relates to the Fermi energy that I have already calculated?
 
Physics news on Phys.org
My question is about band bending. What is it and how do I calculate it?
Is usually covered in your course textbook
I looked through the relevant chapter in my text-book, but I couldn't find any reference to it.
Then the chapter you looked in was not relevant to "band bending" ... look back to where it talks about how energy bands form in the first place - conduction and valence bands etc. Then read forward until you see diagrams of these bands being bent - usually where it starts talking about P-N junctions.

Basically - different materials will have energy bands at different energies.
The bands want to be continuous. The only way this happens for two different materials close enough together for electrical contact is if the bands bend in some way. This usually means that charge carriers get trapped close to the junction or something like that.

See also:
https://www.physicsforums.com/showthread.php?t=626885
https://www.physicsforums.com/showthread.php?t=639129
 
Last edited:
I found the following two equations in my lecture slides. Due to notational differences between my textbook and the lecture slides, I'm not sure if the variable EC represents the band gap energy (which is known in this problem). I am assuming that EFN is the Fermi level energy.

<br /> E_{FN} = E_C - k_B T \times ln(N_C/N_e) \\<br /> E_C - k_B T [ln(N_C/N_e) + ln(N_V/N_h)] = eV_B = E_{FN} - k_B T \times ln(N_V/N_h) <br />

If EC, is the band gap energy does this look like the correct relationship between Fermi Energy and the band bending VB?
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
11K
Replies
1
Views
4K
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
7K