What is Chromoelectric dipole moment?

  • #1

Main Question or Discussion Point

Basically, I wonder what Chromoelectric dipole moment is and how it is formed...
 

Answers and Replies

  • #2
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It is exactly the same thing as an electric dipole moment, but it's generated from color field. Therefore you must be careful about non-commutativity of the charges
 
  • #3
ChrisVer
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The Electric Dipole Moment [itex]\vec{d}_f[/itex] of some particle [itex]f[/itex], is defined by its interaction with an electric field [itex]\vec{E}[/itex]:

[itex] H_{EDM} = - \vec{d}_f \cdot \vec{E}[/itex]

For a spin-1/2 particle, this corresponds to the effective lagrangian density:

[itex] \mathcal{L}_{EDM} = \frac{-i}{2} d_f F_{\mu \nu} \bar{\psi}_f \sigma^{\mu \nu} \gamma^5 \psi_f [/itex]

you can have a similar term if you look at quarks [itex]\mathcal{q}_r[/itex], by replacing the electromagnetism with strong ints:

[itex] \mathcal{L}_{CEDM} = \frac{-i}{2} d_r^{CEDM} G_{\mu \nu}^a \bar{\mathcal{q}}_r \sigma^{\mu \nu} \gamma^5 \frac{\lambda^a}{2} \mathcal{q}_r [/itex]

and that's how it arises... In general both EDMs and CEDMs generate P and T (so CP) violations.
 

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