Orbital magnetic dipole moment of a proton

In summary, the amount of orbital magnetic dipole moment of a proton is a complex and highly debated topic. It is difficult to determine due to the proton's composition as a bound state of quarks and gluons. The commonly used "parton model" does not fully capture the complexities of the proton, which is now described by abstract parton distribution functions. These functions consider not only the three valence quarks but also a "sea" of virtual quarks and gluons. Determining the orbital magnetic dipole moment of the proton involves understanding the contributions of both orbital and spin angular momentum, which can be difficult to separate in relativistic quantum field theories.
  • #1
abdossamad2003
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4
hi every one
what is the amount of orbital magnetic dipole moment of proton? this different with the intrinsic magnetic.
 
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  • #2
What orbit would that be ?

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  • #3
That's in fact a question under vigorous study, and it's very hard to answer. The issue is that the proton is a very complicated bound state of quarks and gluons. A rough model is the "parton model" where it's considered as the bound state of three valence quarks, and this view is historically based on the phenomenology of deep-inelastic electron scattering and the corresponding Bjorken scaling. Today the view has become more complicated, where the proton is described by rather abstract parton distribution functions, where you do not only have three valence quarks somehow bound together in mind but also a "sea" of virtual quarks and gluons and you now ask, how the "bulk properties" of the progon(spin 1/2, the magnetic moment, the mass, charge, etc) is "made up of its constituents". The total spin 1/2 is in this view somehow made up from "orbital and spin angular momentum" of quarks and gluons with the further theoretical problem that in relativistic QFT it's hard to separate spin and angular momentum of elementary particles to begin with, particularly in gauge theories. What's in fact meant by this "split in contributions" are rather abstract "generalized parton-distribution functions".
 
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Related to Orbital magnetic dipole moment of a proton

What is the orbital magnetic dipole moment of a proton?

The orbital magnetic dipole moment of a proton is a measure of the strength and direction of its magnetic field as it orbits around a nucleus.

How is the orbital magnetic dipole moment of a proton calculated?

The orbital magnetic dipole moment of a proton is calculated by multiplying the proton's charge, its angular momentum, and the ratio of its charge to mass.

What is the significance of the orbital magnetic dipole moment of a proton?

The orbital magnetic dipole moment of a proton is significant because it plays a crucial role in determining the magnetic properties of atoms and molecules, and is essential for understanding various physical phenomena such as nuclear magnetic resonance and electron spin resonance.

How does the orbital magnetic dipole moment of a proton differ from its spin magnetic moment?

The orbital magnetic dipole moment of a proton is a result of its orbital motion, while its spin magnetic moment is due to its intrinsic spin. The two moments have different magnitudes and directions, but both contribute to the overall magnetic properties of a proton.

Can the orbital magnetic dipole moment of a proton be measured?

Yes, the orbital magnetic dipole moment of a proton can be measured using various techniques such as nuclear magnetic resonance spectroscopy and electron spin resonance spectroscopy.

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