What is the Acceleration of a Couch Being Pushed at an Angle with Friction?

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Homework Help Overview

The discussion revolves around a physics problem involving the acceleration of a couch being pushed at an angle with friction. The scenario includes a couch with a specified mass, a pushing force at an angle, and a coefficient of friction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the breakdown of the applied force into horizontal and vertical components and calculate the gravitational force. There is an attempt to find the normal force and frictional force, leading to questions about the relationship between these forces and the resulting acceleration.

Discussion Status

Some participants have provided guidance on continuing the calculations, while others express confusion regarding the implications of the results, particularly concerning the acceleration being zero and its interpretation in terms of motion. Multiple interpretations of the problem setup are being explored.

Contextual Notes

There is a lack of clarity regarding the direction of the applied force and its impact on the vertical displacement and normal force. Participants are questioning assumptions about the motion of the couch and the effects of the applied force at an angle.

gullyb
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Homework Statement



An 82 kg couch is being pushed with a force of 56 N at an angle of 40 above horizontal. If the coefficient of friction between the couch and the floor is 0.051, what is the acceleration of the couch?

Homework Equations





The Attempt at a Solution

 
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gullyb said:

Homework Statement



An 82 kg couch is being pushed with a force of 56 N at an angle of 40 above horizontal. If the coefficient of friction between the couch and the floor is 0.051, what is the acceleration of the couch?

Homework Equations



The Attempt at a Solution

Hello gullyb. Welcome to PF !

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ooh sorry,

okay i broke down the fa into its components which i get
fapph=56cos40
fapph=42.9

fappv=56sin40
fappv=36.0

then i found the fg to be 804.42
fg=mg
fg=(82)(9.81)
fg= 804.42

then i solved for fn by making fnet = 0 because the forces cancel out because there is no movement in the vertical direction.
fn=fnet-fg-fappv
fn=0-804.42-36.0
fn=840.42

then i find the force of friction which turns out to be the same as fapph this is where I am stuck, because i don't think they should be the same
ff=uk*fn
=(0.051)(840.42)
=42.9

so if i try to find the acceleration it won't make sense
fnet=ff-faaph
fnet=0
fnet=ma
a=fnet/m

idk what i did wrong please help ?
 
Looks good, keep going, solve for a. What does that imply?
 
well this would mean that the acceleration is 0 so there is no acceleration? but i don't think that is right
 
gullyb said:
a force of 56 N at an angle of 40 above horizontal

I would have interpreted that as pushing upwards. Am I wrong?
 
gullyb said:
well this would mean that the acceleration is 0 so there is no acceleration? but i don't think that is right

Why not? What does it mean if the couch is moving but not accelerating?
 
PhanthomJay said:
Why not? What does it mean if the couch is moving but not accelerating?

hmmm it means that its moving at a constant velocity. ooh okay yes that makes sense thank you! :D
 
  • #10
gullyb said:
hmmm it means that its moving at a constant velocity. ooh okay yes that makes sense thank you! :D

Did you see my comment, post #7?
 
  • #11
haruspex said:
Did you see my comment, post #7?

oooh sorry no, hmm that could be right because they didnt really give any direction to where the couch is going, but i kinda assumed that its moving forward so there won't be any displacement in the vertical direction?
 
  • #12
gullyb said:
i kinda assumed that its moving forward so there won't be any displacement in the vertical direction?
There won't be any vertical displacement provided the upward component is insufficient overcome gravity. But it will reduce the normal force, and hence the friction.
 

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