The acceleration of an electron in a constant electric field can be calculated using the formula F = qE, where F is the force, q is the charge of the electron (-1.6x10^-19 C), and E is the electric field intensity (5.10x10^2 N/C). Given the mass of the electron (9.1x10^-31 kg), the acceleration is determined using Newton's second law, a = F/m. The calculated acceleration is 9x10^13 m/s² directed downwards, confirming the relationship between electric force and acceleration in an electric field.
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That formula is for the electric field of a point charge: you don't need it for this problem. In this problem, the electric field is given. What you do need to know is how much force will that field exert on the electron. The magnitude of the force is given by F = qE.3.14159265358979 said:i know electric field = (kq) / r^2 and F = ma?