What is the acceleration of the car?

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The acceleration of a car sliding down a 10-degree icy driveway is calculated to be 1.7 m/s², derived from the equation a = g sin(10°). The forces acting on the car include its weight, normal force, and the horizontal component of gravitational force. A follow-up question addresses finding the net force needed to accelerate a 110 kg bike and rider from rest to 22.7 m/s in 10 seconds. The correct approach involves first calculating the average acceleration and then applying the formula F = m*a to determine the net force. Overall, the discussion emphasizes the application of basic physics principles to solve motion-related problems.
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A car is slides down an icy driveway that slopes at an angle of 10 degrees. What is the acceleration of the car?


Is the correct answer a=1.70m/s^2?
If it is can someone explain how they figure it out, thanks!
 
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Forces acting on the car:

Weight = mg
Normal = mg cos 10 (deg)
Horizontal = mg sin 10

macar = mg sin 10

cancel out m,

acar = g sin 10 = 1.7 m s-2

So yes, 1.7.
 


Ambidext said:
Forces acting on the car:

Weight = mg
Normal = mg cos 10 (deg)
Horizontal = mg sin 10

macar = mg sin 10

cancel out m,

acar = g sin 10 = 1.7 m s-2

So yes, 1.7.

Ok, thanks. I have another question:

Find the net force (in Newtons) required to accelerate a 110 kg bike and rider from rest to a final velocity of 22.7 m/s in 10 seconds?

since f=ma 110(22.7)=2497 do I divide that by 10 seconds??
 


not exactly...

first solve for average acceleration using equations of motion...
then use the F=m*a and get your answer! :smile:
 
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