What is the acceleration of the car?

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Homework Help Overview

The discussion revolves around calculating the acceleration of a car sliding down an icy driveway inclined at 10 degrees. Participants are exploring the physics of forces acting on the car and the application of Newton's laws.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the car, including weight, normal force, and the component of gravitational force along the slope. There is an attempt to derive the acceleration using these forces. Another participant introduces a new question regarding the net force required to accelerate a bike and rider, prompting further exploration of related concepts.

Discussion Status

Some participants have provided calculations and confirmations regarding the acceleration of the car, while others have suggested a different approach for the bike and rider problem, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

There appears to be confusion regarding the application of formulas and the interpretation of the second question about the bike and rider, which may require clarification on average acceleration and force calculations.

tica86
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A car is slides down an icy driveway that slopes at an angle of 10 degrees. What is the acceleration of the car?


Is the correct answer a=1.70m/s^2?
If it is can someone explain how they figure it out, thanks!
 
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Forces acting on the car:

Weight = mg
Normal = mg cos 10 (deg)
Horizontal = mg sin 10

macar = mg sin 10

cancel out m,

acar = g sin 10 = 1.7 m s-2

So yes, 1.7.
 


Ambidext said:
Forces acting on the car:

Weight = mg
Normal = mg cos 10 (deg)
Horizontal = mg sin 10

macar = mg sin 10

cancel out m,

acar = g sin 10 = 1.7 m s-2

So yes, 1.7.

Ok, thanks. I have another question:

Find the net force (in Newtons) required to accelerate a 110 kg bike and rider from rest to a final velocity of 22.7 m/s in 10 seconds?

since f=ma 110(22.7)=2497 do I divide that by 10 seconds??
 


not exactly...

first solve for average acceleration using equations of motion...
then use the F=m*a and get your answer! :smile:
 

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