- #1

- 79

- 0

Is the correct answer a=1.70m/s^2?

If it is can someone explain how they figure it out, thanks!

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- Thread starter tica86
- Start date

- #1

- 79

- 0

Is the correct answer a=1.70m/s^2?

If it is can someone explain how they figure it out, thanks!

- #2

- 60

- 0

Forces acting on the car:

Weight = mg

Normal = mg cos 10 (deg)

Horizontal = mg sin 10

ma

cancel out m,

a

So yes, 1.7.

- #3

- 79

- 0

Weight = mg

Normal = mg cos 10 (deg)

Horizontal = mg sin 10

ma_{car}= mg sin 10

cancel out m,

a_{car}= g sin 10 = 1.7 m s^{-2}

So yes, 1.7.

Ok, thanks. I have another question:

Find the net force (in Newtons) required to accelerate a 110 kg bike and rider from rest to a final velocity of 22.7 m/s in 10 seconds?

since f=ma 110(22.7)=2497 do I divide that by 10 seconds??

- #4

- 425

- 0

not exactly...

first solve for average acceleration using equations of motion...

then use the F=m*a and get your answer!

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