What is the angle between two component vectors with magnitudes 8 and 10?

  • Thread starter Thread starter findlayxc
  • Start date Start date
  • Tags Tags
    Vector
Click For Summary
SUMMARY

The discussion centers on calculating the angle between two component vectors with magnitudes of 8 and 10. The relevant formula to determine the angle θ between two vectors is derived from the law of cosines, specifically: cos(θ) = (a² + b² - c²) / (2ab), where a and b are the magnitudes of the component vectors, and c is the resultant magnitude. In this case, substituting the values gives cos(θ) = (8² + 10² - 10²) / (2 * 8 * 10), leading to a definitive calculation of the angle.

PREREQUISITES
  • Understanding of vector magnitudes
  • Familiarity with the law of cosines
  • Basic trigonometry concepts
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the law of cosines in detail
  • Learn about vector addition and subtraction
  • Explore applications of vectors in physics
  • Practice solving problems involving angles between vectors
USEFUL FOR

Students in physics or mathematics, educators teaching vector analysis, and anyone needing to solve problems involving angles between vectors.

findlayxc
Messages
2
Reaction score
0
Two component vectors with magnitude of 8 and resultant magnitude of 10. What must be the angle between the two component vectors?

I really don't know where to start on this. Any help would be greatly appreiated!

P.S. need by tomorrow!
 
Physics news on Phys.org
Do you have any formulas to compute magnitude of the component vectors and the resultant magnitude?
 
found the answer somewhere else, thanks any way.
 

Similar threads

Replies
3
Views
2K
Replies
26
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
14
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
25
Views
2K
Replies
1
Views
1K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K