What is the Angular Velocity at a Given Angle for a Given Angular Acceleration?

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SUMMARY

The discussion focuses on calculating angular velocity given an angular acceleration of α = -2ω² rad/s and specific angles θ = π/6 and θ = π/3. The correct approach involves using the relationship between angular acceleration and angular velocity, specifically applying the chain rule to derive the differential equation dω/dt = -2ω². The solution requires integrating the equation while considering the constant of integration, which is determined by the initial conditions provided.

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seboastien
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Homework Statement



angular acceleration of line a= -2w^2 rad/s

when theta=pi/6, w= 10 rad/s

what is angular velocity when theta= pi/3?

Homework Equations



chain rule

The Attempt at a Solution



w= e^-2theta is my answer, but I know this is wrong

I know that this question is really easy, but I just don't know how to get it
 
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Well you should know that α= -2ω2 means that dω/dt = -2ω2

which is an easily solvable DE once you 'separate the variables' i.e. put all the things with ω on one side and t on the other then integrate both sides.
 
But then I end up with t=1/2w, how do I find the rest of the answer?
 
Someone please help me!
 
seboastien said:
But then I end up with t=1/2w, how do I find the rest of the answer?

I now saw that you have ω and θ so forget my above post and replace α with ω*dω/dθ and integrate again. Do not forget the constant of integration which you can find with the conditions they gave you.
 
Yes, that was my problem all along... I forgot to add the constant! Thanks.
 

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