MHB What is the area of triangle $STV$?

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The problem involves finding the area of triangle STV given that the area of triangle XVU is 14 cm². It is established that the area of triangle UVT is three times that of triangle UVX due to equal heights and a base that is three times longer. Consequently, the area of triangle STV is calculated to be 42 cm². This conclusion is reached by applying geometric principles related to base and height in triangles. The solution highlights the relationships between the triangles based on their dimensions.
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Hi all, I happened to see this primary 6 math geometry problem and thought it was a fun (not straightforward but not too hard) problem. Try it and post your solution if you are interested. (Cool)

In the figure, not drawn to scale, $UX=XY=YT$ and $UV=VS$. Given that the area of triangle $XVU$ is 14 cm$^2$, find the area of triangle $STV$.
[TIKZ]
\coordinate[label=left:U] (U) at (0,0);
\coordinate[label=right:T] (T) at (12, 0);
\coordinate[label=below: X] (X) at (4,0);
\coordinate[label=below: Y] (Y) at (8,0);
\coordinate[label=above: V] (V) at (2,1);
\coordinate[label=above:S] (S) at (4,2);
\coordinate[label=above: W] (W) at (7.2,0.4);
\draw (S) -- (U)-- (T)-- (S);
\draw (V) -- (X);
\draw (S) -- (Y);
\draw (V) -- (T);
[/TIKZ]
 
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Area of $\triangle STV$ = area of $\triangle UVT$

because they are on equal base and same base

now area of $\triangle UVT$ is 3 times area of $\triangle UVX$

as height is same and base is 3 times

so area of $\triangle STV$ = 3 * area of $\triangle UVX$ = $42cm^2$
 
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