What Is the Average Acceleration of a Downhill Skier?

  • Thread starter Thread starter never-enough21
  • Start date Start date
  • Tags Tags
    Acceleration Slope
Click For Summary

Homework Help Overview

The discussion revolves around calculating the average acceleration of a downhill skier, with specific values provided for initial and final speeds over a time interval. The subject area pertains to kinematics in physics, particularly focusing on acceleration concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of average acceleration and its calculation, with some expressing confusion about the process. Questions arise regarding the correct interpretation of the formula and the necessary values for initial and final velocities.

Discussion Status

Participants are actively engaging with the problem, with some providing clarifications on the definition of average acceleration. There is an ongoing exploration of the correct approach to the calculation, though no consensus has been reached on the final answer.

Contextual Notes

Some participants question the original poster's understanding of the formula and its application, indicating a need for further clarification on the concepts involved.

never-enough21
Messages
4
Reaction score
0
This might be an extremely easy question and I'm just over-thinking it, but could someone give me a hand with some grade 10 physics?

1. A downhill skier has an initial speed of 2.5 m/s. She accelerates up to a speed of 20 m/s in 3.8 s.

a) Calculate the average acceleration of the skier.


Okay, so I know that acceleration equals velocity over time, but I'm slightly confused. So I know how to calculate the acceleration of 20 m/s in 3.8 s. Which is ... (about) 5.26. But, I get stuck here.
 
Last edited:
Physics news on Phys.org
Why are you confused? Explain.
 
I don't know how to find the average acceleration.
 
Last edited:
wait, is that all I have to do?
 
No, your answer isn't correct. Average acceleration is the change in velocity over a given time interval. So what's the velocity at the beginning of your time interval, and what is it at the end?

Do you recognize this: [tex]a_{ave} = \Delta v / \Delta t[/tex]
 
[tex]a_{ave} = \frac{\Delta v}{\Delta t} = \frac {v_{final} - v_{initial} }{t_{final} - t_{initial} }[/tex]

it is definition :wink:
 
Last edited:

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
2
Views
2K
Replies
20
Views
2K
Replies
2
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
8
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K