What Is the Best Small Electric Motor for Carrying 1000 kg?

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Discussion Overview

The discussion revolves around identifying the best small electric motor capable of lifting a weight of 1000 kg vertically, akin to a helicopter's operation. Participants explore various aspects of motor specifications, including power requirements and mechanical principles involved in lifting heavy loads.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant seeks advice on the best electric motor for lifting 1000 kg vertically, emphasizing the need for a compact size.
  • Another participant inquires about the method of lifting, questioning whether it is vertical or horizontal.
  • A participant clarifies the lifting requirement, indicating the need to lift the weight to a fixed height without continuous ascent.
  • Questions arise regarding the speed of lifting, with a participant asking for specifics on the desired lifting rate.
  • Mathematical calculations are presented by one participant, detailing the power requirement for lifting 1000 kg over a specified distance and time.
  • Further calculations regarding torque and angular velocity are introduced, suggesting the need to adjust motor specifications based on these parameters.
  • Concerns are raised about the feasibility of achieving the required specifications for the motor.

Areas of Agreement / Disagreement

The discussion includes multiple viewpoints on the specifications and requirements for the motor, with no consensus reached on the best approach or solution. Participants express varying levels of understanding and expertise, leading to some confusion about the technical details.

Contextual Notes

Participants express uncertainty regarding specific terms and calculations, indicating a need for clearer definitions and explanations. The discussion reflects a range of assumptions about the lifting mechanism and motor capabilities.

Who May Find This Useful

This discussion may be useful for individuals interested in electric motor specifications, mechanical engineering principles, or those exploring solutions for lifting heavy weights using compact electric motors.

Ibrahim Kamal
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Hello
I want to know what is the best motor can carry 1000 kg
And the weight is not large and also small size
And working with electricity, not fuel

Can you help me
 
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How do you want to carry 1000 kg? To lift it vertically upward, or horizontally?
 
I want to rise vertically, but not continue to rise, such as the helicopter
To reach the high fixed
 
How fast do you need it lifted?
 
Sorry, I'm not an expert so these things can explain more
 
any help please Dickfore
 
Ibrahim Kamal said:
Sorry, I'm not an expert so these things can explain more

Which things?
 
I want to lift the body off the ground for a distance meter and a 1000 km grams all of this on the air like a helicopter and then be fixed
 
I'm sorry I don't know what you mean by this. What helicopter? What does "distance meter and a 1000 km grams" mean?
 
  • #10
Example
To not have a man and weighed 1000 km sitting on a chair and I put motor bottom, bringing the chair to a distance of meters and holds that person
 
  • #11
Do you want it to work on this principle (only bigger):


https://www.youtube.com/watch?v=s6uP1NwhIu0
 
  • #12
Something like this
 
  • #13
If the mass of the load is m, and it is pulled by a constant speed v, then, the power of the motor needs to be at least:
<br /> P = m \, g \, v<br />
where g = 9.81 \, \mathrm{m} \, \mathrm{s}^{-2} is the acceleration of free fall.

For example, if you want to raise a ton (1000 kg) for 15 m (approximately a five story building) in half a minute (30 seconds), you would need a motor with a power:
<br /> 1000 \, \mathrm{kg} \times 9.81 \mathrm{m} \, \mathrm{s}^{-2} \times \frac{15 \, \mathrm{m}}{30 \, \mathrm{s}} = 4905 \, \mathrm{W} \approx 5 \, \mathrm{kW}<br />
 
Last edited:
  • #14
Thank you
i will see it
 
  • #15
Then, you need to adjust the diameter d of the head of the motor to the torque it provides:

<br /> \tau = \frac{m \, g \, d}{2}<br />

The angular velocity (in rpm - rotations per minute) is:
<br /> n = \frac{60 \, v}{\pi \, d}<br />
 
  • #16
wouldn't this kind of hard to achieve?
 

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