What is the binding energy in NaCl?

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SUMMARY

The binding energy of ionic bonds in sodium chloride (NaCl) can be estimated using the formula k*q1*q2 / r, where k is the electric constant, q1 and q2 represent the charges of the ions, and r is the distance between them. In NaCl, sodium (Na) has a charge of +1 and chlorine (Cl) has a charge of -1, leading to the calculation k*(1/6)e*e / r. For other ionic compounds like magnesium oxide (MgO), which has charges of +2 and -2, the binding energy calculation would adjust accordingly, reflecting the different ionic charges.

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  • Understanding of Coulomb's Law
  • Familiarity with ionic bonding concepts
  • Knowledge of electric constants and their applications
  • Basic principles of charge interactions
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  • Research the calculation of binding energy in ionic compounds using Coulomb's Law
  • Explore the differences in binding energy between NaCl and MgO
  • Learn about the role of geometry in ionic bond strength
  • Investigate the impact of ionic charge on binding energy in various compounds
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Homework Statement


Each Na atom transfers 1/6 of an electron, on average, to each Cl atom. Estimate the binidng energy of the ionic bonds in NaCl.


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The Attempt at a Solution


The answer says to use k*q1*q2 / r, where k is the electric constant, q1 and q2 are the charges, and r is the separation between the charges.

So it gives k*(1/6)e*e / r.

I'm wondering what would happen if it were a different atom. In NaCl, Na has a charge of +1 and Cl has a charge of -1. If I wanted to calculate the binding energy of something with charges that weren't necessarily 1, how would this change?
 
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This is based on a simple coulomb interactions between point charges.
 
I know. It's the charges of the ions I'm unclear on. I just wanted to know what the answer would look like if the question was about, say MgO instead of NaCl.
 
MgO would mean charges +2 and -2. 1/6th is just effect of the geometry, so in the case of MgO I would expect 2/6th.
 

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