Calculating Density of NaCl Crystal

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Homework Statement



Calculate the density of crystalline NaCl, given that NaCl has a face-centred cubic lattice with a dimension a = 5.64A.

Homework Equations



1/8 Cl ion at each corner, 1/2 Cl ion on each face. 1 whole Na in the center, 1/4 Na ion along each edge.

The Attempt at a Solution



ok where do i begin
 
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For a FCC structure: corner atoms contribute only 1/8 and face-centered atoms contribute 1/6. So for a FCC system total number of atoms = 8(1/8) + 6(1/2) =4.
But which is corner atom and which is face-centered atom ?
Only idea comes to my mind is:
you should take 'a' as distance between two nearby Cl or Na atom. Then find the kg of NaCl single unit using 'mole' and 'Avogadro' stuff. Also you know volume. So you can compute density.
Hope this help
 
Last edited:
Given - "1/8 Cl ion at each corner, 1/2 Cl ion on each face. 1 whole Na in the center, 1/4 Na ion along each edge." - how would one determine the total atomic mass in the unit cell?

Then given the mass, how would one determined the density?
 

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