What is the boiling point of water on the Z scale?

  • Thread starter Thread starter Shayna
  • Start date Start date
  • Tags Tags
    Scale
Click For Summary
SUMMARY

The boiling point of water on the Z scale is determined to be 167.82 Z. The conversion factor established is that 1 degree Celsius equals 0.5787 Z, derived from the relationship between the boiling point of nitrogen at -190°C and the melting point of steel at 1540°C, which corresponds to 0 Z and 1000 Z respectively. The calculations confirm that 200 Z equals 345.6°C and 618.75 K. The discussion emphasizes the importance of understanding the offset between the Z scale and Celsius for accurate temperature conversions.

PREREQUISITES
  • Understanding of temperature scales, specifically Celsius and Kelvin
  • Basic knowledge of linear conversions between different measurement systems
  • Familiarity with the concept of absolute zero and its implications in temperature measurement
  • Ability to perform mathematical calculations involving ratios and proportions
NEXT STEPS
  • Research the principles of temperature scale conversions, focusing on linear relationships
  • Explore the concept of absolute zero and its significance in thermodynamics
  • Learn about other temperature scales, such as Fahrenheit and their conversion methods
  • Investigate the historical context and applications of unconventional temperature scales
USEFUL FOR

Students and educators in physics, scientists involved in thermodynamics, and anyone interested in unconventional measurement systems will benefit from this discussion.

Shayna
Messages
13
Reaction score
0
A demented scientist creates a new temperature scale, the "Z scale." He decides to call the boiling point of nitrogen 0 Z and the melting point of steel 1000 Z.

What is the boiling point of water on the Z scale?
Convert 200 Z to the Celsius scale.
Convert 200Z to the Kelvin scale.

Attempt solution

Boiling point of nitrogen -190 C
Melting point of Steel 1540 C

1540- (-190) = 1728 C
1728 C = 1000 Z

1.728 C = 1 Z
1 C = 0.5787 Z

Boiling point of water 100C = 57.9 Z
200Z = 345.6 C
200Z = 618.75 K

Mastering physics doesn't like my answer :(
 
Physics news on Phys.org
The first part is correct.
But for the second part you have to take into account the offset between Z and C.
What would 0c be in Z?
It's just the same idea as converting deg F to deg C.
 
I actually didn't quite understand the converting between F and C,
0C in Z Maybe 190C/1728C = X/1000Z therefore 109Z?
Then should 100C in Z be 290/1728 = Z/1000 therefore 167.82?

I think MasPhys liked my answer this time.
Thanks a lot :)
Have a good Thanksgiving.
 
0Z is -190C
1 C = 0.5787 Z
so 0C is 190*0.5787 Z = 109.9 Z
so Z is = 109.9 + C*0.5787
therefore 100 degC = 109.9 + 57.87 = 167.82 degZ
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 40 ·
2
Replies
40
Views
9K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 9 ·
Replies
9
Views
135K
Replies
1
Views
10K
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
8K