What is the Bug's Velocity Relative to the Road?

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SUMMARY

The bug's velocity relative to the road is determined by the principle of relative velocity. When the car moves eastward at 12.0 m/s and the bug flies eastward at 2.0 m/s relative to the car, the bug's velocity relative to the road is 14.0 m/s eastward. Conversely, if the bug flies westward at 2.0 m/s relative to the car, its velocity relative to the road is 10.0 m/s eastward. This analysis utilizes the formula for relative velocity, V1 = V2 - V3, where V1 is the relative velocity of the bug, V2 is the car's velocity, and V3 is the bug's velocity relative to the car.

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Homework Statement


car moving 12.0m/sec eastward on straight road. inside car, bug is flying eastward at 2.0m/s relative to the car. how fast is the bug moving relative to the road? repeat for the bug moving westward.


Homework Equations





The Attempt at a Solution



i assume the westward movement will be a negative ratio
 
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You know how relative velocity works?

Its like this:

V1(Relative velocity of body 'a' wrt to body 'b') = V2(Velocity of body 'a' wrt ground) -
V3(Velocity of body 'b' wrt ground)

Yes the westward movement will be -ve quantity if u take the eastward motion of car as +ve.
 
Last edited:
what about average acceleration? is that distance/time?
 
Change in displacement over time is velocity. Changes in velocity over time is acceleration.

Average acceleration is the average acceleration over a period of time, say t1 (10.30am) and t2 (10.32am). Then if the velocity v1 at t1 was 40km/hr and the velocity v2 at time t2 was 30km/hr, the average acceleration would be:

(v2-v1) divided by (t2-t1) = (-10km/hr) per (2 mins) = -5 km/hr per min
which is interpreted as a slow down of 5km/hr in velocity every minute, over the past 2 minutes.
 

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