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Velocity after a totally inelastic collision

  1. Sep 16, 2015 #1
    1. The problem statement, all variables and given/known data
    You are driving your 1000-kg car at a velocity of(25 m/s )ι^ when a 9.0-g bug splatters on your windshield. Before the collision, the bug was traveling at a velocity of (-1.5 m/s )ι^.
    What is the change in velocity of the car due to its encounter with the bug?

    2. Relevant equations
    pi = pf
    m1v1 + m2v2 = (m1 + m2)v

    3. The attempt at a solution
    p1 + p2 = (m1 + m2)v
    (2.5 x 10^4) + (-1.35 x 10^-2) = (1000 + 0.009)v
    v = 25 m/s
     
  2. jcsd
  3. Sep 16, 2015 #2
    So is there a question here?
     
  4. Sep 16, 2015 #3
    Yes. The question is "What is the change in velocity of the car due to its encounter with the bug?". I also came up with an answer but it was incorrect.
     
  5. Sep 16, 2015 #4
    You got the correct equation for the final velocity, and I am just going to re-write it out for you as follows:

    $$v=\frac{(2.5 \times 10^4-1.35 \times 10^{-2})}{1000+0.009}$$

    If you subtract the original velocity of the car, you get the change in velocity Δv:

    $$Δv=\frac{(2.5 \times 10^4-1.35 \times 10^{-2})}{1000+0.009}-25$$

    Now, what I would like you to do is to reduce the relationship to a common denominator, without first evaluating the first term and without combining terms in the numerator. What do you get?

    Chet
     
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