1. The problem statement, all variables and given/known data A small 13.0g bug stands at one end of a thin uniform bar that is initially at rest on a smooth horizontal table. The other end of the bar pivots about a nail driven into the table and can rotate freely, without friction. The bar has mass 65.0g and is 120cm in length. The bug jumps off in the horizontal direction, perpendicular to the bar, with a speed of 25.0cm/s relative to the table. mass bug = 0.013 kg mass bar = 0.065 kg distance from axis of rotation = 1.2 m velocity bug = 0.025 m/s Find What is the angular speed of the bar just after the frisky insect leaps? 2. Relevant equations L = Iω I(bug) = Mr^2 ω(bug) = v/r L(bug) = Iω = Mr^2ω = Mrv I(bar) = Mr^2 ω(bar) = v/r L(bar) = Iω = Mr^2ω 3. The attempt at a solution Conservation of Angular Momentum L(bug) = L(bar) M*r*v = M*r^2*ω 0.013*0.12*0.025 = 0.065*0.12^2*ω 3.9*10^5 = 9.36*10^4ω ω = 0.204 Conservation of Kinetic Energy KE = 1/2Iω^2 KE(bug) = 1/2Iω^2 KE(bug) = 1/2(mr^2)ω^2 KE(bug) = 1/2(mr^2)(v/r)^2 KE(bug) = 1/2mv^2 KE(bar) = 1/2Iω^2 KE(bar) = 1/2(1/3mr^2)ω^2 KE(bar) = 1/6mr^2ω^2 KE(bug) = KE(bar) 1/2mv^2 = 1/6mr^2ω^2 4.0625E-6 = 0.0156ω^2 ω^2 = 2.6042E-4 ω = 0.01614 So far none are correct. Please Help!