What is the capacitance of each capacitor?

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SUMMARY

The discussion centers on calculating the capacitance of two capacitors, C1 and C2, given their equivalent capacitances in parallel (9.00 pF) and in series (1.55 pF). The equations used are C1 + C2 = 9.00 pF for parallel and (1/C1) + (1/C2) = (1/1.55 pF) for series. The solution involves substituting C1 = 9 - C2 into the series equation, leading to a quadratic equation that can be solved for the individual capacitances. This method provides a definitive approach to finding the values of C1 and C2.

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Two capacitors when connected in parallel give an equivalent capacitance of 9.00 pF and an equivalent capacitance of 1.55 pF when connected in series. What is the capacitance of each capacitor?

in parallel:
C1 + C2 = 9.00 pF

in series:
(1/C1) + (1/C2) = (1/1.55pF)

My attempt:
(C1 + C2)/(C1*C2) = 1/1.55

(C1*C2)/(C1+C2) = 1.55

(C1*C2)/9 = 1.55

C2 = (9*1.55)/C1

From here i don't know what to do...
 
Last edited:
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You have two equations and two unknowns. Solve for one in terms of another and plug it into a 2nd equation.
 
Just put C1 = 9 - C2 from the first equation, into the second equation and solve the resulting quadratic equation.
 
thanx guys :)
 

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