What is the capacitance of each capacitor?

AI Thread Summary
The discussion centers on calculating the capacitance values of two capacitors based on their equivalent capacitances when connected in parallel and series. The parallel connection yields a total capacitance of 9.00 pF, while the series connection results in 1.55 pF. The user attempts to derive the individual capacitances using equations derived from these configurations. They are advised to express one capacitor's value in terms of the other and substitute it into the second equation to solve the resulting quadratic equation. The conversation highlights the methodical approach to solving simultaneous equations in capacitor networks.
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Two capacitors when connected in parallel give an equivalent capacitance of 9.00 pF and an equivalent capacitance of 1.55 pF when connected in series. What is the capacitance of each capacitor?

in parallel:
C1 + C2 = 9.00 pF

in series:
(1/C1) + (1/C2) = (1/1.55pF)

My attempt:
(C1 + C2)/(C1*C2) = 1/1.55

(C1*C2)/(C1+C2) = 1.55

(C1*C2)/9 = 1.55

C2 = (9*1.55)/C1

From here i don't know what to do...
 
Last edited:
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You have two equations and two unknowns. Solve for one in terms of another and plug it into a 2nd equation.
 
Just put C1 = 9 - C2 from the first equation, into the second equation and solve the resulting quadratic equation.
 
thanx guys :)
 

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