What is the cause of the pull on the charged metal plate?

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The discussion centers on calculating the outward pull on a charged circular metal plate with a radius of 10 cm and a charge of 20 microCoulomb. The formula used is F = [σ²]A / (2εK), where σ is the surface charge density calculated as Q/A. The area A is determined using the equation πr², and it is clarified that only one surface of the plate is considered for this calculation, as the plate is not in an electric field. The presence of an electric field is necessary for the plate to experience a pull.

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1. A circular metal plate of radius 10cm is given a charge of 20 microCoulomb. Determine the outward pull on the plate, k=1

i can solve the problem by using the equation F= [sigma ^2]A / 2 epsilon* K and finding [tex]\sigma[/tex] = Q/A {where A= area of surface(plate), Q = charge}

My problem:
to find area of plate i used the equation pi *r^2; or do i need to consider 2[tex]\pi[/tex]r^2 as plate have two surfaces.
 
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sphyics said:
1. A circular metal plate of radius 10cm is given a charge of 20 microCoulomb. Determine the outward pull on the plate, k=1

i can solve the problem by using the equation F= [sigma ^2]A / 2 epsilon* K and finding [tex]\sigma[/tex] = Q/A {where A= area of surface(plate), Q = charge}

My problem:
to find area of plate i used the equation pi *r^2; or do i need to consider 2[tex]\pi[/tex]r^2 as plate have two surfaces.

I want to help you, but I'm stuck as to understand why there is a pull on the plate. Is it situated in an electric field?
 
fluidistic said:
I want to help you, but I'm stuck as to understand why there is a pull on the plate. Is it situated in an electric field?

i havn't thought that way, ofcourse what i feel is u r right :) inoder to experience a pull there must be presence of electric field, i.e it must be placed in an electric field. or it must experience an electric field. like if the part under consideration is a part of larger conductor and the charges are spread uniformly, through the larger one, then smaller part of that conductor will experience a force.
 

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