What is the change in density of water at a depth of 400 m?

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SUMMARY

The change in density of water at a depth of 400 meters can be calculated using the formula New Density = Initial Density * (1 / (1 - dP/B)), where the initial density is 1030 kg/m³ and the bulk modulus (B) of water is 2 x 109 N/m². The change in pressure (dP) can be determined using the equation dP = h * surface density * g. This approach is valid despite the variation in density with depth, as the surface density can be used for calculations at this depth.

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Abhishekdas
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Bulk modulus question...please help

Homework Statement


What is the change in density of water in a lake at a depth of 400 m below the surface? The density of water at the surface is 1030 kg/m3 and bulk modulus of water is 2*109 Nm2


Homework Equations


For fluid
New Density= Initial density*(1/1-dP/B)
dP=change in pressure and B=bulk modulus


The Attempt at a Solution



My doubt is can we apply dp=h*density*g here taking the initial density (1030) because density is not constant throughout...Do we have to integrate or something...? What do do?
 
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ANy replies here...please...
 


Abhishekdas said:
ANy replies here...please...

You can take P = h X surface density X g
 

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