What is the change of variable for proving the fractional part integral?

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alyafey22
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Prove the following
$$\int^1_0 \left \{ \frac{1}{x} \right \} \, dx = 1- \gamma $$​
 
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ZaidAlyafey said:
Prove the following
$$\int^1_0 \left \{ \frac{1}{x} \right \} \, dx = 1- \gamma $$​

[sp]With the change of variable $\displaystyle \frac{1}{x}= t $ the integral becomes...

$\displaystyle \int_{0}^{1} \{\frac{1}{x}\}\ d x = \int_{1}^{\infty} \frac{\{t\}}{t^{2}}\ d t = \sum_{n=2}^{\infty} \int_{n-1}^{n} (\frac{1}{t} - \frac{n-1}{t^{2}})\ d t = \lim_{n \rightarrow \infty} (\ln n - \sum_{k=2}^{n} \frac{1}{k})= 1 - \gamma$[/sp]

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$\chi$ $\sigma$